A differentiable function f(x, y) has the property that f(2, 2) = 5 and fa(2, 2) = -5 and fy(2, 2) = -3. Find the equation of the tangent plane at the point on the surface z = f(x, y) where x = 2, y = 2. Z=
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- Find the equation of the tangent plane to the surface y = 2x2 2a - z2 at the point (0,-1, 1)Find an equation of the tangent z = 4x² - y² + 2y, plane to the given surface at the specified point. (-2, 4, 8)Find a parametric description for the curve y=4-x^2 from (-2, 0) to (2, 0) such that t=0 corresponds to (-2, 0)
- Find the equation of the tangent line to the curve of intersection of the surface z = x² - y² with the plane x = 9 at the point (9, 1,80). (Express numbers in exact form. Use symbolic notation and fractions where needed.) equation:A differentiable function f(x, y) has the property that f(3,4) = 4 and fa (3, 4) = -1 and ,(3,4) = 4. Find the equation of the tangent plane at the point on the surface z = f(x, y) where x = 3,y = 4. 2 =Find an equation of the tangent plane to the surface 9x2 + y2 + 4z2 = 25, at the given point (0, −3, 2).
- Find an equation of the tangent plane to the surface z = 4x2- 2y? + 3x + y at the point ,-2,-3)Find the tangent plane to the equation z = z = 3x² - y² + 4y at the point (2,-1,-17)Find equations for all the planes that intersect the y-axis at y = 1 and the z-axis at z = 2, and are tangent to the sphere (x-2)^2 + y^2 + z^2 = 4. Do not use calculus
- Find equations of the tangent plane and normal line to the surface x = 5y² + 5z² - 28 at the point (-3, -1, -2). Tangent Plane: (make the coefficient of x equal to 1). = 0. Normal line: (-3, +t(1, ☐☐).`Find an equation of the tangent plane to the surface x3 + 2z²ey¬x = 136 at point P = (4, 5, 2). (Use symbolic notation and fractions where needed.) = 1 help (fractions)Determine the coefficients a, b, c and d so that the curve y = ax* + bx³ + cx² + dx + e will pass through the points (0, 3), (–2,7) and have an inflection point at (1,4) with horizontal tangent.