A) Determine the pH of the solution that results from the mixing of 60.0 mL of 0.100 M NaOH, 94.0 mL of 0.0500 M KOH, 62.5 mL of 0.075 M HCl, 37.0 mL of 0.065 M HNO3, and 3.00 quarts of distilled water.

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A: Molarity of HCl = 0.1 M Volume of HCl = 10 mL Molarity of NaOH = 0.1 M Volume of NaOH = 10 mL Moles…

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A: Answer: In acid-base reaction, neutralization takes place where hydrogen ions and hydroxide ions…

Q: the molarity of the NaOH solution used

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Q: A student performs a titration and records the following data: Initial buret volume:  11.87 mL…

A: The moles of NaOH used in this titration is = 0.004049 (or) 4.049 × 10-3

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A: Acid and base netralize each other.

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A: Given  Volume of NaOH ( V1 ) = 27.20 mL  Molarity of NaOH ( M1 ) = 0.150 M  Volume of HCl ( V2 )…

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A: D option is correct. pH = 2.15 so, nearly solution is 2.11.

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A: We have CH3CH2COOH →CH3CH2COO- + H+ Concentration of propanoic = 0.17 M  Ka=1.3 x 10-5

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.