A computer has four page frames. The time of loading, time of last access, and the R and M bits for each page are as shown below (the times are in clock ticks) Page Loaded Last ref. R M 126 280 1 1 230 265 1 140 270 3 110 285 1 1 When page fault occurs, NRU removes page number

Q: A computer has four page frames. The time of loading, time of last access and the R and M bits for…

A: The Answer is

Q: A computer has four page frames. The time of loading, time of last access and the R and M bits for…

A: The Answer is in step2

Q: The time of loading, time of last access, and the R and M bits for each page are as show (the times…

A: Given: Computer system has 4 page frames and the following table: Page  Loaded   Last ref.      R…

Q: Given: Page or frame size = 2 bytes No. of process page 8 pages No. of memory frames = 16 frames…

A: 9

Q: A computer has four page frames. The time of loading, time of last access and the R and M bits for…

A: The Answer is in Below Steps:-

Q: Consider a paging system with the page table stored in memory. 80 percent of all page-table…

A: Here in this question we have given a paging system in which 80 % of all page table reference found…

Q: A computer has four page frames. The time of loading, time of last access, and the R and M bits for…

A: a) NRU-It means  Not recently used. it will replace that page having R and M bit is zero.…

Q: w. (Note that each hexidecimal is 4 bits long and 0x means prmat Page Table Physical Physical…

A: For any given virtual address, the least significant 16 bit of physical address and virtual address…

Q: In the demand paging memory, a page table is held in registers. If it takes 1000 ms to service a…

A: To find the effective access time for a page fault rate.

Q: In the demand paging memory, a page table is held in registers. If it takes 1000 ms to service a…

A: GIVEN:

Q: In the demand paging memory, a page table is held in registers. If it takes 1000 ms to service a…

A: page service time s=1000ms memory access time/miss memory time T=20ms Page fault rate=p=0.01…

Q: For a system that uses 10-KB page size, calculate the page number and offset for the "200001"…

A: The formula for calculating Page number = (address reference / page size) This is the page number…

Q: Assignment 2 Page Replacement A computer has four page frames. The time of loading, time of last…

A: The answer is given below:-

Q: In a paged memory, the page hit ratio is 0.40. The time required to access a page in secondary…

A: Answer: We have a given value: Page_Hit_Ratio(PHR) = 0.40 Secondary_Memory(SM) = 120ns…

Q: In a paged memory, the page hit ratio is 0.40. The time required to access a page in secondary…

A: Introduction :       Given,         paged memory         page hit ratio=0.40         second memory…

Q: In a 12-bit machine with page size of 128, we have a physical address of 1000 1001 1011. What is the…

A: Given physical address=100010011011=2203 Page size=128

Q: Given a scenario where there are four frames. The following table shows the loading time of a page…

A: Im providing the answer of the above question. I hope this will help..

Q: If a system has Total Memory = 120 MB, Process = 60 MB, Frame Size = 4 MB What will be the page…

A:

Q: For a page size of 200 words, what is the page number and offset for a logical address of 1142

A: Given: Page size = 200 words  Logical address = 1142 We need to find the page number and offset.

Q: For a page size of 200 words, what is the page number and offset for a logical address of 1142

A: Given data is 200 words page size  page number and offset for a logical address of 1142

Q: For a system that uses 4-KB page size, calculate the page number and offset for the "96312" address…

A: Given  page size = 4KB = 4000 Bytes Address reference = 96312

Q: n a paged memory, the page hit ratio is 0.40. The time required to access a page in secondary…

A: Introduction :Given , a paged memory .page hit ratio = 0.40memory access(secondary) = 120 nsmemory…

Q: !In a two-level paging system, each page table entry is 16 bytes and the page size is 16 KB. How…

A:

Q: Consider a paging hardware with a TLB. Assume that the entire page table and all the pages are in…

A: Translation lookaside buffer (TLB):- A translation lookaside buffer (TLB) is a memory cache that…

Q: Consider a paging system with the page table stored in memory. a. If a memory reference takes 400…

A: Since, number of memory accesses required by a paged memory reference = 2   Time taken by a memory…

Q: If the page size in a 32-bit machine is 4K bytes then the size of the page table?

A: Introduction :Givenphysical address size (PA)=32 bitslogical address size (LA)=32 bitswe have to…

Q: (b) Consider a paging system with the page table stored in memory. If a memory reference takes 200…

A: Ans:-  a) If memory access takes 200 nanoseconds, how long does a paged memory reference take?200…

Q: Consider a paging system with the page table stored in memory. a. If a memory reference takes 50…

A: The Answer is in Below Steps:-

Q: Consider a paging system with the page table stored in memory. a. If a memory reference takes 50…

A: The Answer is in step2

Q: For a system that uses 8-KB page size, calculate the page number and offset for the "6070281"…

A: Paging is a memory management strategy that does away with the need for contiguous physical memory…

Q: Suppose the time to service a page fault is on the average 10 milliseconds, while a memory access…

A: Question. Suppose the time to service a page fault is on the average 10 milliseconds, while a memory…

Q: If the page size in a 32-bit machine is 4K bytes then the size of page table is :

A: Introduction :Given , 32-bit machine Page size = 4 K Byte Then, we have to calculate the size of…

Q: a memory reference takes 10 ns (nanoseconds), how long does a paged m mke? we add TLBS, and if 90…

A: A) Paged memory reference takes 20 ns Total 20 nanoseconds 10 nanoseconds to access the page table…

Q: For a computer system using a 64 bit width data path, how many number of a bits will this computer…

A: А  соmрuter  аlоng  with  аdditiоnаl  hаrdwаre  аnd  sоftwаre  tоgether  is  саlled  а  соmрuter…

Q: Given references to the following pages by a program: 4, 2, 3, 9, 3, 2, 5, 4, 6, 3, 5, 4, 9, 3, 6,…

A: Given pages,  4, 2, 3, 9, 3, 2, 5, 4, 6, 3, 5, 4, 9, 3, 6, 9, 4, 6, 3, 1, 6, 1, 2, 1. Number of…

Q: b) Suppose we have 512-bit logical address with 16KB of page size. Calculate the following: (i)Inner…

A:

Q: en a 12 bit address space and the Page/Frame size is 64 How many bits are there for theloffset? How…

A: A)  Number of bits for offset = log 2 (page size)  = log 2 64 = 6 bits

Q: Part 1 A small computer on a smart card has four page frames. At the first clock tick, the R bits…

A: Aging Algorithm Initially all the counters have 0 value specified in 8-bit notation. The R bits for…

Q: Assuming a 1 KB page size, what are the page numbers and offsets for the following address…

A: Page size = 1KB So page offset = log 1KB = 10 bits A.  2562 = 101000000010 Page offset = 1000000010…

Q: Consider a paging system with the following: Physical memory= 32 bytes. Page size=4 bytes. Page…

A: We are given a question in which we are given physical memory size 32bytes . Our physical address is…

Q: If a system has a 4-MB address space, where each page is 4 KB, and page table accesses take 100 nS,…

A: Given Data :  Size of Address Space = 4 MB  Size of the page = 4 KB  One page tablet/page access…

Q: Consider a paged virtual memory system with 12 bit virtual addresses & IKB pages Each page table…

A: The answer for number of levels page tables are

Q: A machine has 48-bit virtual addresses and 32-bit physical addresses. Pages are 8 KB. How  many…

A: Actually, given information: A machine has 48-bit virtual addresses  32-bit physical addresses.

Q: Suppose we have already the page table shown below, what happens when CPU generates address 3000?…

A: Given:

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: The answer is

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: The answer is

Q: Determine the number of page table entries (PTES) that are needed for the following combinations of…

A: The connection between page table entries, virtual location size and page size is given as  Page…

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: The answer is as follows:-

Q: Address Content 50 10 51 57 52 21 OA 53 54 52 55 01 56 32 57 58 CO 59 00 Suppose the memory cells at…

A: Here, I have to answer the above question.

Q: Let the page fault service time be 10 ms in a computer with average memory access time being 20 ns.…

A: It is given that viable memory access time without page shortcoming = 20 ns. Presently, subbing…