A computer employs RAM chips of 128 x 8 and ROM chips of 512 x 8. The computer system needs 256 bytes of RAM, 1024 x 16 of ROM, and two interface units with 256 registers each. A memory mapped I/O configuration is used. The two higher -order bits of the address bus are assigned 00 for RAM, 01 for ROM, and 10 for interface registers. a. Compute total number of decoders are needed for the above system?
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- A computer employs RAM chips of 512 x 8 and ROM chips of 256 x 8. The computer system needs1K bytes of RAM, 2K bytes of ROM, and eight interface units, each with 2 registers. A memory-mapped1/0 configuration is used. The two highest-order bits of the 16 bit address bus are assigned 10 for RAM,11 for ROM, and 00 for interface registers.a. How many RAM and ROM chips are needed?b. Draw a memory-address map for the system.c. Give the address range in hexadecimal for RAM, ROM, and interface.A modern computer central processing unit chip (CPU) runs with a clock speed of 2.7 GHz. It can execute one operation in each of these clock cycles. a. How many seconds long is one clock cycle? b. Electrical signals travel at the speed of light. How far can an electrical signal travel in one clock cycle? c. Wires between the CPU's control unit and its cache memory (both on this chip), are about 2 cm long. How does this compare to how far an electrical signal can travel in one clock cycle?A computer employs RAM chips of 128 x 8 and ROM chips of 512 x 8. The computer system needs 1K bytes of RAM, 2K bytes of ROM, and two interface units, each with two registers. A memory-mapped 1/0 configuration is used. The two highest-order bits of the 16-bit address bus are assigned 11 for RAM, 10 for ROM, and 01 for interface registers.a. How many RAM and ROM chips are needed?b. Draw a memory-address map for the system.c. Give the address range in hexadecimal for RAM, ROM, and interface
- A computer employs RAM chips of 512 x 16 and ROM chips of 1024 x 8. The computer system needs 4K bytes of RAM and 2K bytes of ROM along with interface unit of 128 registers each. A memory mapped I/0 configuration is used. The two higher order bits are assigned for RAM, ROM and interface as 00, 01 and 10 respectively. a) How many RAM and ROM chips are neededA computer system contains a big endian byte addressable memory system with 8 separate memory modules. Each memory module is 32 bits wide and contains 134217728 cells. Cells within each memory module are numbered 0 through 134217727. a) If the memory employs high order interleaving, what is the 32-bit memory address of cell 1048578 within module 3? b) If the high order interleaved memory uses little-endian instead of big-endian storage order, what is the 32-bit memory address of cell 511 within module 1? c) If the memory employs low order interleaving, what is the 32-bit memory address of byte 1048575 within module 2? Bytes are numbered starting from 0. Express the address in hex. d) What is the main advantage of using low-order interleaved memory compared to using high-order interleaved memory?A computer employs RAM chips of 512 x 16 and ROM chips of 1024 x 8. The computer system needs 4K bytes of RAM and 2K bytes of ROM along with interface unit of 128 registers each. A memory mapped I/O configuration is used. The two higher order bits are assigned for RAM, ROM and interface as 00, 01 and 10 respectively. •a. Compute total number of decoders are needed for the above system? •b. Design a memory-address map for the above system •C. Show the chip layout for the above design
- Suppose we have a byte-addressable computer using fully associative mapping with 16-bit main memory addresses and 32 blocks of cache. Supposed also that each block contains 16 bytes. The size of the offset field is 19 bits and the size of the block field is 0.625 bytes.On the Motorola 68020 microprocessor, a cache access takes two clock cycles. Data access from main memory over the bus to the processor takes three clock cycles in the case of no wait state insertion; the data are delivered to the processor in parallel with delivery to the cache. a. Calculate the effective length of a memory cycle given a hit ratio of 0.9 and a clocking rate of 16.67 MHz. b. Repeat the calculations assuming insertion of two wait states of one cycle each per memory cycle. What conclusion can you draw from the results?Let's pretend for a moment that we have a byte-addressable computer with 16-bit main memory addresses and 32-bit cache memory blocks, and that it employs two-way set associative mapping. Knowing that each block has eight bytes, please calculate the size of the offset field and provide evidence of your calculations.
- Consider a word-addressable computer with 32 bits per word. The instruction set consists of 30 different All instructions have an operation code field, a mode field to specify one of 7 possible addressing modes, a register address field to specify one of 60 available registers, and a memory address field. Each instruction is stored in one word of memory. What is the maximum allowable size for memory? Use KB, MB, or GB as a unit.A computer with a 32-bit 3.5 gigahertz scalar non- pipelined CPU needs to invert the colors of a 150 KB bitmap image file located in the RAM. To do this, each bit of the image must be complemented (Os are converted to 1s and vice-versa). Assume every instruction undergoes the following stages and each stage uses one CPU clock cycle: • Fetch • Decode • Read from memory • Execute • Write to memory Instructions: For this assignment, you must calculate how much time the computer will need to invert the image with a single-core and a dual core CPU. Show and explain your calculations and assumptions in a short paper and answer the following questions: • Will there be any parallel slowdown? Why or why not? Length: 2-3 page explanatory paperConsider a CPU which operates with 20Mbyte/s operating speed. The CPU is operating on program control mode of I/O and it has to transfer data of 20 bytes from it. The data is transferred byte wise. Size of the Status register is 2 bytes. What is the total time needed to perform the data transfer?