CErClaimPull evidence that shows the student is incorrectInclude reasoning .T-Mobile LTEAIsotopeK-39K-41mistry student at Agora is calculating the average atomic mass of Potassium using the following data.Relative abundance93.12 %6.88 %Their setup and calculation are.Mass (amu)11:07 AM38.96440.962Atomic Mass38.964 amu40.962 amuX Relative Abundance (% divide by100)0.06880.931233%= 2.681= 38.14440.823 amu×The student calculated the average atomic mass to be 40.823 amu but it is 39.098 amu on the periodic table.What did the student do incorrectly? Use CER!

Answered: Image /qna-images/answer/57279751-109d-4657-bf90-babafedb41bf.jpg

A Chemistry student at Agora is calculating the average atomic mass of Potassium using the following data. Relative abundance Isotope K-39 K-41 Their setup and calculation are. Mass (amu) 93-12% 6.88% 38.964 40.962 X Atomic Mass 38.964 amu 40.962 amu Relative Abundance ( divide by 100) 0.0688 0.9312 = 2.681 = 38.144 40.823 amu The student calculated the average atomic mass to be 40.823 amu but it is 39.098 amu on the periodic table. What did the student do incorrectly? Use CER!

A Chemistry student at Agora is calculating the average atomic mass of Potassium using the following data. Relative abundance Isotope K-39 K-41 Their setup and calculation are. Mass (amu) 93-12% 6.88% 38.964 40.962 X Atomic Mass 38.964 amu 40.962 amu Relative Abundance ( divide by 100) 0.0688 0.9312 = 2.681 = 38.144 40.823 amu The student calculated the average atomic mass to be 40.823 amu but it is 39.098 amu on the periodic table. What did the student do incorrectly? Use CER!

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter2: Chemical Compounds

Section: Chapter Questions

Problem 27QRT

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Similar questions

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