A 140 lb weight stretches a spring 14 feet. The weight hangs vertically from the spring and a damping force numerically equal to 5√7 times the instantaneous velocity acts on the system. The weight is released from 7 feet above the equilibrium position with a downward velocity of 30 ft/s. (a) Determine the time (in seconds) at which the mass passes through the equilibrium position. (b) Find the time (in seconds) at which the mass attains its extreme displacement from the equilibrium position. Round your answer to 4 decimals. Round your answer to 4 decimals.

icon
Related questions
Question
A 140 lb weight stretches a spring 14 feet. The weight hangs vertically from the spring and a damping force
numerically equal to 5√√7 times the instantaneous velocity acts on the system. The weight is released from 7 feet
above the equilibrium position with a downward velocity of 30 ft/s.
(a) Determine the time (in seconds) at which the mass passes through the equilibrium position.
(b) Find the time (in seconds) at which the mass attains its extreme displacement from the equilibrium position.
Round your answer to 4 decimals.
Round your answer to 4 decimals.
Transcribed Image Text:A 140 lb weight stretches a spring 14 feet. The weight hangs vertically from the spring and a damping force numerically equal to 5√√7 times the instantaneous velocity acts on the system. The weight is released from 7 feet above the equilibrium position with a downward velocity of 30 ft/s. (a) Determine the time (in seconds) at which the mass passes through the equilibrium position. (b) Find the time (in seconds) at which the mass attains its extreme displacement from the equilibrium position. Round your answer to 4 decimals. Round your answer to 4 decimals.
Expert Solution
steps

Step by step

Solved in 4 steps with 18 images

Blurred answer