9.6 Using D flip-flops, design a logic circuit for the finite-state machine described by the state assigned table in Figure P9.6. Present Next State Output State x=0 x=1 y21 Y2Y1 Y2Y1 Z 00 00 01 0 01 10 11 00 888 00 11 0 00 10 0 10 1 Figure P9.6
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- Using D flip-flops, design a logic circuit for the finite-state machine described by the state assigned table in Figure P9.6. Present State Y2V1 00 01 10 11 Next State x = 0 Y₂Y₁ 00 00 00 00 x = 1 Y2Y₁ 01 11 10 10 Figure P9.6 Output Z 0 0 0 1Using D flip-flops, design a logic circuit for the finite-state machine described by the state assigned table in Figure P9.10. Present State Y2Y1 00 01 10 11 Next State x = 0 Y2Y1 01 00 11 10 x = 1 Y2Y₁ 10 11 00 00 Figure P9.10 x=0 Z 0 0 0 0 Output x = 1 Z 1 0 0 1Using D flip-flops, design a logic circuit for the finite-state machine described by the state assigned table in Figure P9.6. Present Next State Output State x=0 x=1 Y2V1 Y2Y1 Y2Y1 Z 00 00 01 01 10 88 00 11 00 00 10 0 11 00 10 1 I need a step by step solution
- 9.9 Using D flip-flops, design a logic circuit for the finite-state machine described by the state assigned table in Figure P9.9. Present Next State Output State x=0 x=1 x=0 x=1 yayı Y2Y1 Y2Y1 N N 852= 00 01 10 11 8888 00 01 0 0 00 11 0 0 00 10 0 0 00 10 0 1 Figure P9.99.8 Using D flip-flops, design a logic circuit for the finite-state machine described by the state assigned table in Figure P9.8. Present Next State Output State x=0 x=1 x=0 x=1 y21 Y2Y1 Y₂Y1 Z Z 00 00 01 0 0 01 10 11 883 00 10 0 0 00 10 0 1 00 10 1 1 Figure P9.8Design the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).
- Q2/A) Design 8x1 multiplexer using 2x1 multiplexer? Q2 B)Simplify the Logic circuit shown below using K-map then draw the Simplified circuit? Q2/C) design logic block diagram for adding 12 to 5 using full adder showing the input for each adder?You want to design an arithmetic comparison combined logic circuit. (a) List the steps that you will apply in the design approach. Design a 4-bit comparison (large-equal-small) circuit. Explain each step. With AND, OR, NOT gatesmake it happen. (b)By comparing the numbers 9 and 1 in the circuit you designed, the resultdiscuss.Q) You want to design a synchronous counter sequential (sequential) logic circuit. Counting from 9 to 0 and will not count the last digit of your student number. (a) List the steps that you will apply in the design approach. State Chart and State Create the table. (b) Design the sequential circuit using JK Flip-Flop. Explain each step. Desired action show that you have done it. " last digit student num:4 " Not : I want the solution to contain tables and equations, and the electrical circuit resulting from tables and equations, as in the picture that I attached,And if possible, I want the solution on paper if possible.
- logic circuit diagram for fabinaaci counter that gives output in fabinaaci sequence.upto 2 digits please mentions the gates and ics used in circuit.Design Master-Slave Flip Flop circuit diagram and write a short description.Up/Down State Machine Cousider a state machine implementation of a two bit up/down counter mput: up/doun, and two outputs: Outo and Out,, which also indicate the next state. When up/dowTI is high, the counter counts up (00,01,10,11,00, ). When up/doun is low, the counter counts down (00,11.10.01.00, ..). The state machine has one Part A Complete the state diagram below by adding all required transition arcs with input annotations. Output annotations are not required since they correspond to the new state. state state 00 01 state state 10 11