1:53 PM Sun Oct 9R₂, Y₁₁6=√24¾/2Idx √24 a peT9) For the 2p, orbital, what is the most probable point (r, 0, d) where an e- will be found.-9/2"Pest) ² = 034T COSO= (1 += COSO )² = 010:52V@ 79%++:9

Answered: Image /qna-images/answer/7c937233-99ad-402e-aa8f-d8c463d55a3b.jpg

9) For the 2p, orbital, what is the most probable point (r, 8, d) where an e- will be found. R₁, Y₁ = fi ce -$12 3 2,1 1,0 √24 a. pe 3/2 "pe²³ ) ² = 0 d Z dx √24 a. pe 4T COSO 2 (COSO )² = 0

9) For the 2p, orbital, what is the most probable point (r, 8, d) where an e- will be found. R₁, Y₁ = fi ce -$12 3 2,1 1,0 √24 a. pe 3/2 "pe²³ ) ² = 0 d Z dx √24 a. pe 4T COSO 2 (COSO )² = 0

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter6: The Periodic Table And Atomic Structure

Section: Chapter Questions

Problem 13CO: • identify an orbital (as 1s, 3p, etc.) from its quantum numbers, or vice versa.

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Question

1:53 PM Sun Oct 9
R₂, Y₁₁6=
√24
¾/2
I
dx √24 a pe
T
9) For the 2p, orbital, what is the most probable point (r, 0, d) where an e- will be found.
-9/2
"Pest) ² = 0
3
4T COSO
= (1 += COSO )² = 0
10:52
V
@ 79%
+
+:
9

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