7. ERROR OF CLOSURE. Given the following tabulated data fo1 two transit-tape surveys: LATITUDE DEPARTURE LINE LENGTH BEARING +N -S +E - W s 06°35'w N 17°48'w N 70°59'w N 59°33'E S 39 1 8'E 51.09 99.88 410.79 1-2 445.66 m 442,72 2-3 3-4 311.09 141.68 326.73 434.50 4-5 427.00 216.40 368.10 5-1 301.95 233.66 191.25 Sums 1935.84 m + 669.07 -676.38 +559 35 -561.76 (D) (ENL) (ESL) CEED) EWD) LATITUDE DEPARTURE COURSE AZIMUTH FROM NORTH LENGTH ++ -- +E - W 227:57 82° 12' 131 48' 228 20' 267 43' 352*01' AB 229.70 m 31.17 97.32 BC CD 87.02 107.34 130.55 120.61 161.46 180. 35. 23.86 DE 7.19 180.49 171.83 EA 170.16 Sums 874.03 m +201.33 -201.55 +324.89 -324.82 (D) (ENL) (ESL), (EED) (ZWD) For each traverse determine the linear error of the irection of the side of error. the measurements made. Tabulate all observed ànd values. closúre, and the precision of computed

7. ERROR OF CLOSURE. Given the following tabulated data fo1 two transit-tape surveys: LATITUDE DEPARTURE LINE LENGTH BEARING +N -S +E - W s 06°35'w N 17°48'w N 70°59'w N 59°33'E S 39 1 8'E 51.09 99.88 410.79 1-2 445.66 m 442,72 2-3 3-4 311.09 141.68 326.73 434.50 4-5 427.00 216.40 368.10 5-1 301.95 233.66 191.25 Sums 1935.84 m + 669.07 -676.38 +559 35 -561.76 (D) (ENL) (ESL) CEED) EWD) LATITUDE DEPARTURE COURSE AZIMUTH FROM NORTH LENGTH ++ -- +E - W 227:57 82° 12' 131 48' 228 20' 267 43' 352*01' AB 229.70 m 31.17 97.32 BC CD 87.02 107.34 130.55 120.61 161.46 180. 35. 23.86 DE 7.19 180.49 171.83 EA 170.16 Sums 874.03 m +201.33 -201.55 +324.89 -324.82 (D) (ENL) (ESL), (EED) (ZWD) For each traverse determine the linear error of the irection of the side of error. the measurements made. Tabulate all observed ànd values. closúre, and the precision of computed

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question2 Course LAT DEP DMD 2A 172.5 11.5 12.55 AB 15 11.5 BC 16.75 33.55 595.4625 CD -20.45 27.65 -815.675 DE -5.75 -13.25 -6.05 34.7875 EA 3.50 -9.65 -33.775 a. What is the length of course CD, express in 2 decimal places b. What is the departure of course EA, express in 2 decimal places c. What is the area of the traverse, express in 2 decimal places. Do not include negative sign
7. ERROR OF CLOSURE. Given the Eollowing tabulated data for two transit-tape surveys: LATITUDE DEPARTURE LINE LENGTH BEARING +N +E - W s 06°35' W N 17 48'w N 70 59 w N 59°33'E S 39° 1 a'E 1-2 445.66 m 442.72 51.09 2-3 326.73 311.09 99.88 3-4 434.50 1 41.58 410.79 4-5 427.00 216.40 368.10 5-1 301.95 233.66 191.25. Sums 1935.84 m + 669.07 -676.38 +559 35 -561.76 (D) (ENL) (ESL) CEEDI E WD)
Asiacell A docs.google.com/f :D TIITME. LIIVUI If Ø=0.987643 rad. Find Ø in bläj 3 degrees 35° 25' 25" 56° 35' 16" 65° 25' 13" O 45° 42' 16" O 54° 30' 16" 52° 04' 26" blä 3 When a level is in adjustment, the line of sight of the * instrument is
Following are the data gathered from the traverse: Lat Dep DPD 2A 399.790 0 565.388565.277 -350.184605.780 -564.112-205.360 -50.882-965.697 Express all answer unitless and with 3 decimals for A to J No new data to sav
HM 36 Q.3 A level circuit is shown in figure. The survey, needed for local engineering project, commenced at BM 35, the elevation of new benchmarks 36, 37, 38 and 39 were determined, and then the level survey was looped back to BM 35, the point of commencement. Fined the adjusted new BMs. ВМ 35 Elevation(m) 119.010(fixed) 35 36 37 38 39 35 123.342 118.206 118.451 120.491 118.933 09 km. DM 35 O8 km DBM 37 08 km 08 km BM 39 BM 38 0.7 km
From the following observations, what is the closing error? Line AB BC CA O Length (m) 92.96 157.63 131.24 a. 1.44 O b. 1.99 C. c. 1.55 O d. 1.66 Latitude +92.57 -317.39 +226.19 Departure -217.92 +24.62 +192.36 <
9. COMPASS the observed and calculated data for two different transit- tape surveys: RULE. Given in the accompanying tabulations are LINE LATITUDE DEPARTURE DISTANCE BEARING +N -S +E - W 1-2 388.08 m S 52 51'w N 00°42'E S 85 57'E S 03°04'W 234.36 309.32 2-3 732.72 732.67 8.95 3-4 324.78 477.24 22.94 323.97 4-17 476.56 25.53 Sums 1922.82 m +732.67 -733.86 +332.92 -334.85 (D) (ENL) ESL) (ZED) (EWD) LATITUDE AZIMUTH FROM SOUTH COURSE DISTANCE DEPARTURE + N - S + E -W 1-2 180 50' 116 06' 25 54 315 20' 213 27' 275 39' 475.48 m 475.43 6.92 2-3 649. 13 867.34 285.58 582.94 3-4 780.22 378.86 4-5 522.48 371.59 367.29 5-6 504.90 421.27 278.31 6-1 311.25 30.64 309.74 Sums 3330.58 m +1182.28 -1182.45 -961:80 +962.26 (D) (ENL) (ESL) (EED) (E WD) For closure, the survey after the latitudes and departures are by to a suitable scale the adjusted traverse. set of survey data, dírection of the side of error, each determine the mis- and precision, of balanced Tabulate values accordingly and draw linear…
Find the missing data and complete the table below. DIST (m) 23.324 27.459 ? 69.771 22.361 20.591 20.616 15.811 LINE AB BC CD CD DE EF FG GH HA Missing data: LINE Bearing N 30° 58' E N 56° 53' E ? S 27° 18' W N 26° 34' W S 60° 57' W N 14° 2¹ E N 71° 34' W DISTANCE (M) DIRECTION BEARING ANGLE (°)
Q1. Calculate departures and latitudes of the following ABCDE traverse. 3 N A 285.40' •N26°10'E E 5 75 25 E 640.45' 647.02' 5306 W N 0°42' W 720.8 203.00 5 15 30¹ W
(a) Briefly explain the main reason the used of transition curves, how the transition curve is used in road geometry design and the purpose of super-elevation in combine road curve design. Q3. (b) Two straights, Al and IB, whose bearings are DDD° AI' Al" and DDD° IB' IB" respectively intersect at point I, are to be connected by a combined curve. The chainage of point / is CCCC m, while the design speed and radius have been fixed at 90 km/h and 550 m respectively. Adopting a rate of change of acceleration of 0.3 m/s. As a civil engineer have been assign to do a trial analysis of the proposed design of horizontal combine curve (T1, T2, T3 and T4) and prepared road curve setting-out data (T1 to T2, T2 to T3, T3 to T4) at 20 m intervals using deflection angle and chord distance method. (c) By adopting the coordinate of intersection point / as (YYYY N, XXXX E). Calculate the coordinate of tangent point for T1, T2, T3 and T4.
9. COMPASS the observed and calculated data for two different transit- tape surveys: RULE. Given in the accompanying tabulations are LINE LATITUDE DEPARTURE DISTANCE BEARING +N -S +E -W 1-2 S 52 51'w N 00°42'E S 85 57'E 203°04'w 388.08m 234.36 309.32 2-3 732.72 732.67 8.95 3-4 324.78 22.94 323.97 4-1 477:24 476.56 25.53 Sums 1922.82 m +732.67 +332.92 -733.86 -334.85 (D) (ENL) ESL) (ZED) EWD) LATITUDE AZIMUTH FROM SOUTH COURSE DISTANCE DEPARTURE -W 1-2 475.48 m 180 50' 116° 06' 25 54' 315 20' 213 27' 275 39' 475.43 6.92 2-3 649. 13 285.58 582.94 378.86 3-4 867.34 780.22 371.59 4-5 522.48 367.29 5-6 504.90 421.27 278.31 6-1 311.25 30.64 309.74 Sums 3330.58 m +1182.28 -1182.45 +962.26 -961.80 (D) (ENL) (ESL) (EED) (E WD) For closure, the survey after the latitudes and departures are by to a suitable scale the adjusted traverse. each set of survey data, direction of the side of error, determine the mis- and precision, of balanced Tabulate values accordingly and draw linear the compass…
FOR A GIVEN TRAVERSE. SUPPLY THE TABLE WITH THE MISSING DATA AND ANSWER THE QUESTION BELOW: LINES ADJ. LATITUDE ADJ. DEPARTURE DMD АВ +16.37 +5.96 BC +6.92 +17.12 CD -20.77 +8.39 DE -9.65 -8.10 EF -4.79 -9.01 FA +11.92 -14.36 A. SUMMATION OF POSITIVE DOUBLE AREAS(round to 2 decimal places) B. SUMMATION OF NEGATIVE DOUBLE AREAS (round to 2 decimal places) C. SUMMATION OF DOUBLE AREAS round to 2 decimal places) D. AREA OF THE TRAVERSE: round to 2 decimal places)