6. Discussion: 4. What is the relationship type in the plot between (Fexp) versus (p QVJ)? Why? 5. Is there a difference between the slope from plot and the slope of the value (1-Cos)? Why?
6. Discussion: 4. What is the relationship type in the plot between (Fexp) versus (p QVJ)? Why? 5. Is there a difference between the slope from plot and the slope of the value (1-Cos)? Why?
Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
5th Edition
ISBN:9781305084766
Author:Saeed Moaveni
Publisher:Saeed Moaveni
Chapter14: Computational Engineering Tools Electronic Spreadsheets
Section: Chapter Questions
Problem 20P
Related questions
Question
![6. Discussion:
4. What is the relationship type in the plot between (Fexp) versus (p Q VJ)?
Why?
5. Is there a difference between the slope from plot and the slope of the
value (1- Cos)? Why?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F917afcee-0c9b-444b-8927-1b609b47dfdb%2F09ec4f8f-3b39-493b-b572-b645e52985d6%2F8axtivd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6. Discussion:
4. What is the relationship type in the plot between (Fexp) versus (p Q VJ)?
Why?
5. Is there a difference between the slope from plot and the slope of the
value (1- Cos)? Why?
![Calculation
time = 28, Volume = 5, mass: 70, h = 5. __
VOL
5
1=0.17 m²/sec
(V₁ = = 0.17
time
28
12.56
A = I ² = = ~(4) = 12.56 m² / V5= Vn -√2gh
= 0.013-√2016)
=83.64
FJ=9Q VJ (1-cose)
=(1/(0-17) (83.64) (1-C0545)
= 4.265
90-45, time = 32, Volume = 5, mass=140
/V₁=
Q = Vol = 5= 0.15 m²/sie
tim 32
..15
12.56
A=Id=-(6)=12.56² / V5= Vn -√2gh
=0.011-√√2x 140.50
= 118.3
FJ=A@v₂ (1-cosys)
=(1)(0.15) (118.3) (0.31
= 5.323
J
0=45
= 0.013 mhu
h: 50mm
= 0.011 m/s.c
Calculation
D 0=9 time=19, mass: 1oo, ho 50mm, Volume 5
Vol 50.26 m²/see
time 19
/ Vni
V₁ = @=
0.26
12.56
A= d² = (16) = 12.56 m² / V5= V₁-√2gh
=0.02-√2x100 50
= 100
FJ=PQV₂ (1-C059)
=(1) (0-26) (100) (1-0)
= 26
90-9:
time = 23, mass = 70, h = 50mm, Volum. 5
VOL
5
0.21
/V₁==
= 0.21 m²/91.
1256
23
A=Id': (6) = 12.56 m²
VS-Vu-Jegh
= 0.016-√2+70×5
FJ= POV, (1-cosq:)
= 83.64
=(1) (0.21) 183.64)(1)
= 17.56
= 0.02 m/sec
= 0.016 m/s.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F917afcee-0c9b-444b-8927-1b609b47dfdb%2F09ec4f8f-3b39-493b-b572-b645e52985d6%2F9h14osp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Calculation
time = 28, Volume = 5, mass: 70, h = 5. __
VOL
5
1=0.17 m²/sec
(V₁ = = 0.17
time
28
12.56
A = I ² = = ~(4) = 12.56 m² / V5= Vn -√2gh
= 0.013-√2016)
=83.64
FJ=9Q VJ (1-cose)
=(1/(0-17) (83.64) (1-C0545)
= 4.265
90-45, time = 32, Volume = 5, mass=140
/V₁=
Q = Vol = 5= 0.15 m²/sie
tim 32
..15
12.56
A=Id=-(6)=12.56² / V5= Vn -√2gh
=0.011-√√2x 140.50
= 118.3
FJ=A@v₂ (1-cosys)
=(1)(0.15) (118.3) (0.31
= 5.323
J
0=45
= 0.013 mhu
h: 50mm
= 0.011 m/s.c
Calculation
D 0=9 time=19, mass: 1oo, ho 50mm, Volume 5
Vol 50.26 m²/see
time 19
/ Vni
V₁ = @=
0.26
12.56
A= d² = (16) = 12.56 m² / V5= V₁-√2gh
=0.02-√2x100 50
= 100
FJ=PQV₂ (1-C059)
=(1) (0-26) (100) (1-0)
= 26
90-9:
time = 23, mass = 70, h = 50mm, Volum. 5
VOL
5
0.21
/V₁==
= 0.21 m²/91.
1256
23
A=Id': (6) = 12.56 m²
VS-Vu-Jegh
= 0.016-√2+70×5
FJ= POV, (1-cosq:)
= 83.64
=(1) (0.21) 183.64)(1)
= 17.56
= 0.02 m/sec
= 0.016 m/s.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Recommended textbooks for you
![Engineering Fundamentals: An Introduction to Engi…](https://www.bartleby.com/isbn_cover_images/9781305084766/9781305084766_smallCoverImage.gif)
Engineering Fundamentals: An Introduction to Engi…
Civil Engineering
ISBN:
9781305084766
Author:
Saeed Moaveni
Publisher:
Cengage Learning
![Engineering Fundamentals: An Introduction to Engi…](https://www.bartleby.com/isbn_cover_images/9781305084766/9781305084766_smallCoverImage.gif)
Engineering Fundamentals: An Introduction to Engi…
Civil Engineering
ISBN:
9781305084766
Author:
Saeed Moaveni
Publisher:
Cengage Learning