(6) A parallel-plates capacitor with plate area of 100 cm? has a separation of 3mm between the pates. The separation is divided into three slabs, where each slab has 1 mm distance. The first slab is filled by air and has a constant of 1. The second slab is filled by polystyrene and has a constant of 2.5, while the third slab is filled by silicon dioxide and has a constant of 4. Compute the capacitance of the system. Note: for parallel slabs; Conductor 1 E = Air E1 E2 E3 Material A Material 3 Conductor

Delmar's Standard Textbook Of Electricity
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ISBN:9781337900348
Author:Stephen L. Herman
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Chapter19: Capacitors
Section: Chapter Questions
Problem 3RQ: A capacitor uses air as a dielectric and has a capacitance of 3 F. A dielectric material is inserted...
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(6) A parallel-plates capacitor with plate area of 100 cm? has a separation of 3mm between the
pates. The separation is divided into three slabs, where each slab has 1 mm distance. The first slab
is filled by air and has a constant of 1. The second slab is filled by polystyrene and has a constant of
2.5, while the third slab is filled by silicon dioxide and has a constant of 4. Compute the
capacitance of the system.
Note: for parallel slabs;
Conductor
1
E = T
1
Air
E1
83
Material A
Material 3
Conductor
Ans. C = 54 pF
Transcribed Image Text:(6) A parallel-plates capacitor with plate area of 100 cm? has a separation of 3mm between the pates. The separation is divided into three slabs, where each slab has 1 mm distance. The first slab is filled by air and has a constant of 1. The second slab is filled by polystyrene and has a constant of 2.5, while the third slab is filled by silicon dioxide and has a constant of 4. Compute the capacitance of the system. Note: for parallel slabs; Conductor 1 E = T 1 Air E1 83 Material A Material 3 Conductor Ans. C = 54 pF
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