50 uL of an aqueous sample of double-stranded DNA is dissolved in 950 uL of water. This diluted solution has a maximal absorbance of 0.326 at 260 nm. What is the concentration of the original (more concentrated) DNA sample, expressed in ug/ul? I would like to know the process of this question. And I was wondering as well if the total diluted volume would be 950ul + 50ul = 1000ul

50 uL of an aqueous sample of double-stranded DNA is dissolved in 950 uL of water. This diluted solution has a maximal absorbance of 0.326 at 260 nm. What is the concentration of the original (more concentrated) DNA sample, expressed in ug/ul? I would like to know the process of this question. And I was wondering as well if the total diluted volume would be 950ul + 50ul = 1000ul

Macroscale and Microscale Organic Experiments

7th Edition

ISBN:9781305577190

Author:Kenneth L. Williamson, Katherine M. Masters

Publisher:Kenneth L. Williamson, Katherine M. Masters

Chapter14: Ultraviolet Spectroscopy, Refractive Indices, And Qualitative Instrumental Organic Analysis

Section: Chapter Questions

Problem 4Q

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50 uL of an aqueous sample of double-stranded DNA is dissolved in 950uL of water. This diluted solution has a maximal absorbance of 0.326 at 260 nm. What isthe concentration of the original (more concentrated) DNA sample, expressed in ug/ul? I would like to know the process of this question. And I was wandering as well if the total diluted volume would be 950ul + 50ul = 2000ul
50 uL of an aqueous sample of double-stranded DNA is dissolved in 950 uL of water. This diluted solution has a maximal absorbance of 0.326 at 260 nm. What is the concentration of the original (more concentrated) DNA sample, expressed in ug/uL?
You are measuring the concentration of an unknown protein sample, and the absorbance at 595 nm (or A595) of your unknown is greater than that of the highest-concentration standard solution. It is not advisable to simply extrapolate the line of the standard curve to calculate the concentration of the unknown In this scenario, what would be the best strategy to measure the concentration of your unknown (instead of extrapolating from the standard curve)?
Guanosine has a maximum absorbance of 275 nm. ϵ275= 8400M−1cm−1 and the path length is 1 cm. Using a spectrophotometer, you find the that A275=0.70. What is the concentration of guanosine?
A direct ELISA experiment was done to determine the amount of protein present in a sample. A standard curve was prepared by plotting log Absorbance versus log concentration of protein in (ng/mL). The equation of the line is Y= 0.895 X -1.25. If an unknown protein shows an absorbance of 1.23. Calculate the concentration of this protein in the sample in (ng/mL).
Calculate the specific absorbance ratio (SAR), where A620 = 0.166 and A280 = 0.557
What does the absorbance of a protein at 280 nm reflect and how does that information help you determine the protein concentration of a sample if you know the sequence of your protein?
How did you decide on the wavelength at which you will read the absorbance of the diluted solutions? What is the importance of reading the absorbance of diluted solutions at λmax? What will vary if you chose a wavelength 20 nm lower or higher than your chosen wavelength? (Minimum of 8 sentences)
You obtained the following raw data when setting up a Biuret standard curve: Absorbancy 540nm BSA (mg/ml) 0.158 1 0.210 2 0.260 3 0.305 4 0.360 0.410 0.455 7 0.510 8 0.530 9 0.550 10 0.554 After blanking against a biuret-dH20 sample, the protein concentration of an unknown sample was determined using the same method and an absorbancy of 0.279 was obtained. Set up a standard curve, excluding outliers (experimental and statistical) and determine the protein concentration in the unknown sample in mg / ml (up to 3 significant figures).
Q1: The concentration of yeast t-RNA in an aqueous solution is 10 M. The absorbance is found to be 0.209 when this solution is placed in a 1.00 cm cuvette and 258 nm radiations are passed through it. a) Calculate the specific absorptivity, including units, of yeast t-RNA. b) What will be the absorbance if the solution is 4 M? c) What will be the absorbance if the path of the original solution is increased to 7.00 cm?
Chlorophyll absorbs photons strongly in two bands, one between 340 and 450 nm and the other between 650 and 680 nm. Chlorophyll collects and transfers the photon energy to fix CO2 into carbohydrate CH2O units according to CO2 + H2O → (CH2O) + O2 where the (CH2O) indicates one carbon unit of the carbohydrate. The average enthalpy change for the addition of a carbon unit to a carbohydrate is ΔH = 485 kJ/mol. What is the minimum number of 660 nm photons needed by chlorophyll to add a carbon unit to a carbohydrate? (Remember that there’s no such thing as a partial photon.) Please no copy paste from anywhere
Chlorophyll absorbs photons strongly in two bands, one between 340 and 450 nm and the other between 650 and 680 nm. Chlorophyll collects and transfers the photon energy to fix CO2 into carbohydrate CH2O units according to CO2 + H2O → (CH2O) + O2 where the (CH2O) indicates one carbon unit of the carbohydrate. The average enthalpy change for the addition of a carbon unit to a carbohydrate is ΔH = 485 kJ/mol. What is the minimum number of 660 nm photons needed by chlorophyll to add a carbon unit to a carbohydrate? (Remember that there’s no such thing as a partial photon.) Please no copy paste