5 Given: design speed = 100 kph, (f = 0.13), p = 0.4 m/sec3 , Sta. Pl = 5+ 000.000 Roadwidth = 14.0 m (4-lane, 2-way), Normal crown = 1.5 %, Intersection angle = 30° Designthe section of highway. I

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Answered: 5 Given: design speed = 100 kph, (f =…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Given: design speed = 100 kph, (f = 0.13), p = 0.4 m/sec3 , Sta. PI = 5 + 105.000 Roadwidth = 14.0 m (4-lane, 2-way), Normal crown = 1.5 %, Intersection angle = 27° Designthe section of highway. (ans: The highway has the properties of a clothoid withLc=114.194m, and e=0.034)
1. On a divided highway with project speed of 90 kph, slopes of two red lines gi= %3,4 and g2= -%2,8, connect at an intersection point with 0+50000 km and elevation of 200,00 m. Please calculate: a. Length of vertical curve, b. Elevation at red line at points T1, T2 and every 15 m. (treact= 0,75sn, f=0,60).
The data given for a vertical sagcurve on a roadway plan andprofile sheet are as follows: PVIstation @ 32+11.61, PVI elevation =54.18 ft, back tangent gradient g1 =- 4.00 percent, forward tangentgradient g2 = + 7.00 percent, andlength of curve L= 600ft. Determinethe curve elevations at half-station intervals along the curve,and compute the station andelevation of the lowest point. PLEASE PROVIDE COMPLETE AND COMPREHENSIVE SOLUTION AND FINAL ANSWER ASAP
A six-lane road has a curve radius of 1,350 ft. Each lane is 12 ft. wide. SSD = 570 ft. What is M₂? A. 21 ft. B. 31 ft. C. 41 ft. D. 51 ft.
Compute the cross sectional area for the roadway section at station 10+33.89 using the following cross section data. The width of the roadway is 50 feet. -25 25 25 25 F 11.8 -42.5 F 14.3 -32.0 F 15.8 F 16.3 65.4
For the following conditions: Design speed 60 mph, V/C ratio = 0.6, Level of service = Curve radius, 955 ft, Time value = $4/hr. If the basic section cost for passenger cars on a multilane highway is $206/KV-M, estimate the highway grade. B, %3D
Assignment 3: Vertical Curve Design Question 2 The reduced level at the intersection of a rising gradient of P % and a falling gradient of Q % on a proposed road is XX.XX m. Given that K value is KK. The throught chainage of the intersection point is YYYY.YY m and proposed vertical curve is to have equal tangent. As a civil engineering you are required to prepare the following vertical curve design calculations: a) The through chainage of the points of the vertical curve if the minimum required length is to be used (Lv) and the vertical curve setting out data at 20 metres interval. b) The chainage and reduced level of the highest point on the curve. c) Through chainage at highest point was located exactly under a bridge, if the RL of soffit is SS.SS m, calculate the headroom based on proposed vertical curve design.
Imagine a two lane highway segment with crown slopes of -1.5% and the start of the tangent runout at St.Km.0+000.00.The design speed is 75 km/hr. The Radius of the circular curve is 408 m.Prepare a small superelevation table showing superelevations of each travel laneatthe startand endof the tangent runout,at the start and end of the superelevation runoffand at the point of curvature only. Notes: Make sure emax< 0.08, take Sr 1/200. Use Turkish Practice
Calculate the end area for the following stations with 30-ft wide roadway and 4:1 slop: Sta Left Center Right 14+00 F4.0/31.00 F5.0/0.00 F7.0/19.00 15+00 F6.0/25.00 F7.0/0.00 F8.0/17.00
The highway engineer of a certain road construction decided to use a radius of 100 m. in laying out a simple curve having an angle of intersection of 36'20', The stationing of the vertex is 30 + 375.20 after verifying the actual conditions of the proposed route, it was found out that the P.T. should be moved out in a parallel tangent having a perpendicular distance of 10 meters with the angle of intersection remaining the same while the curve shall have the same P.C. O Compute the new tangent distance. @ Compute the new radius.of curve. 3 Compute the stationing of new P.T.
A-3% grade us connected to a +1.0% grade by means of 180m vertical curve. The point of intersection (PI) is at station 0+100 and its elevation is 100m above sea level. Compute the direct distance from the lowest point on the curve, to the point of intersection of the tangent lines (Pl). Add your answer
. A+4.5% grade on rural free way intersects with a-2.5% grade at chainage of 67+500 at an elevation 75.00. If the design speed of free way us 100km/hr. N.b obtain the value of (k) from the following table # determine the chainage and elevation of the Bvc, Evc and the lowest point #if the road is stacked at 50m interval, calculate the elevations of all full chainage a long the curve. Table. minimum value of k for vertical curve. Design speed crest value sag value 40 6 8 50 11 2 60 16 16 70 23 20 80 33 25 90 46 31 100 60 36 110 81 43 120 110 52 130 133 57

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5 Given: design speed = 100 kph, (f = 0.13), p = 0.4 m/sec3, Sta. Pl = 5 + 000.000 Road width = 14.0 m (4-lane, 2-way), Normal crown = 1.5 %, Intersection angle = 30° Design the section of highway. I %3D