40. Black hamster fur is dominant to white hamster fur. What are the possible genotypes and phenotypes for a cross between two parent hamsters heterozygous for fur color? Complete the Punnett square to support your answer.

40. Black hamster fur is dominant to white hamster fur. What are the possible genotypes and phenotypes for a cross between two parent hamsters heterozygous for fur color? Complete the Punnett square to support your answer.

Name: 40. Black hamster fur is dominant to white hamster fur. What are the
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Description: 40. Black hamster fur is dominant to white hamster fur. What are the possible genotypes and phenotypes for across between two parent hamsters heterozygous for fur color? Complete the Punnett square to supportyour answer.

Science Of Agriculture Biological Approach

5th Edition

ISBN:9780357229323

Author:Herren

Publisher:Herren

Chapter4: The Science Of Genetics

Section: Chapter Questions

Problem 1SLA

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What is the correct table in these two given? 1. Take two coins and assume that heads represent the dominantallele (A) and tails represents the recessive allele (a). The genotype for each coin isheterozygous (Aa).2. Assume that each coin represents one parent. When a single coin is flipped, one gameteis formed (through the process of meiosis). If the flipped coin is on heads, then thegamete has the dominant allele (A). When both coins are flipped simultaneously, therewill be two possible gametes that can combine through fertilization to form a zygote. Eachtime you flip both coins, you will record the “genotype” of the offspring.3. Flip the coins 100 times and record your results in the chart below
38 Which cross would produce phenotypic ratios that would best illustrate the Law of Dominance? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. TT X tt TT X Tt tt X tt TTX TT 身

[ ] Complete the following table considering mating a black hearing male Labrador dog (homozygous in both alleles) with black deaf female (heterozygous in coat color allele). ] Genotype structure of the male "Genotype structure of the female ]Possible gamete structure(s) of the male s] Possible gamete structure(s) of the female ]What are the traits of the resulting offspring if a sperm bD fertilizes an egg bd? Key: B= black allele (dominant), b = brown allele (recessive), D = hearing allele (dominant), d = deaf allele (recessive). %3D
25. a)What is “dihybrid cross”? b) Consider two traits color and height. For color, let Y=yellow be dominant over y=green; for height, let T=tall be dominate over t=short. i. Set up the P1 generation ii. enumerate the possible gametes in the sex cells iii. Put the possible gametes along the top and sides of a Punnett square. iv. Hence, or otherwise, find a) the proportion (in percentage) of the F1 are yellow and tall with genotype YyTt b) The probability of obtaining, the genotype YyTt
Purple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口ロ口

man, assume that spotted skin (S) is dominant over non-spotted skin (s) and that wooly hair (W) is dominant over non-wooly hair (w). Cross a marriage between a heterozygous spotted, non-wooly man with a heterozygous wooly-haired, non-spotted woman. Give the genotypes and phenotype of offspring.
Incomplete Dominance: 1) On the planet Iota Geminorum IV there exists a small hairy animal known as a tribble. It comes in three colors blue, red, and purple. This trait is controlled by a single locus with incompletre dominance. A homozygous CBCB is blue, a homozygous CRCR is red, and a heterozygous CBCR is purple. a. What would be the genotypes and phenotypes of the offspring if a blue tribble were crossed with a red one? b. If the offspring in #1 were crossed what would the genotypic and phenotypic ratios be of this generation?
Black eye (B) is dominant over brown eye (b). A man that is a homozygous dominant black-eyed marries a woman that is a heterozygous black-eyed. The offspring resulted to 50% homozygous black and 50% heterozygous black. If one of their heterozygous children marries another heterozygous partner. Regardless of its gender, what are the genotypes of their children? a. 25% BB, 50% Bb, 25% bb b. 50% BB, 25% Bb, 25% bb c. 25% BB, 25% Bb, 50% bb d. 0% BB, 75% Bb, 25% bb In Law of Codominance, a pure line dominant trait crossed with a recessive trait will result to the appearance of both dominant and recessive trait in the offspring. What is the percentage of having a red-haired offspring if the parental genotype is both a heterozygous roan haired? Red hair is a dominant trait and white hair is a recessive trait. a. 100% b. 75% c. 50% d. 25% e. 0%
In guinea pigs, the black coat (B) is dominant over the white coat (b), and straight hair (H) is dominant over curly hair (h). Using a Punnett square, complete the cross between a heterozygous black, curly-haired individual and a homozygous straight-haired, white individual. State the parent genotypes and gametes, and the F1 phenotypes and genotypes.
Given the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the phenotype of this individual be?
Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has color blindness only, and 1 has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness?
As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women. During his tenure as guard, he had numerous clandestine affairs. In each case, children resulted. Subsequently, some of the childrenwho had no way of knowing that they were relatedmarried and had children of their own. Assume that two pairs of genes determine height. The genotype of the 7-foot-tall Potsdam Guard was A9A9B9B9, and the genotype of all of his 5-foot clandestine lovers was AABB. An A9 or B9 allele in the offspring each adds 6 inches to the base height of 5 feet conferred by the AABB genotype. a. What were the genotypes and phenotypes of all the F1 children? b. Diagram the cross between the F1 offspring, and give all possible genotypes and phenotypes of the F2 progeny