4) Consider the following circuit. a) find the frequency and the phase angle of the source. b) find the current 1₁ w R₁ = 1 k c) find the current I R2 - 3 ΚΩ C=0.2 µF V5 cos(3000+π/2) V in L = 0.5 H
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- An RC series circuit is connected to a 120-V, 60-Hz power source. The resistor is 25 and has a voltage drop of 65 volts. What is the capacitance of the capacitor?A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating of 600 WVDC. The capacitor and resistor are connected to a 480-V, 60-Hz circuit. Is the voltage rating of the capacitor sufficient for this connection?Capacitive Circuits Fill in all the missing values. Refer to the formulas that follow. XC=12fCC=12fXCf=12CXc Capacitance XC Frequency 38 F 60 Hz 78.8 400 Hz 250 pF 4.5 k 234 F 10 kHZ 240 50 Hz 10 F 36.8 560 nF 2 MHz 15 k 60 Hz 75 nF 560 470 pF 200 kHz 6.8 k 400 Hz 34 F 450
- Multicolour LED Mono LED Dimensional LED The capacitor in a clamper circuit is in parallel with the voltage source * None True False For the following circuit, the vo waveform is wwwwwCBASFEED BUCK 300L 20 桃 1: 200 € 200a student is doing work on circuit in which he employs a voltage af 60 sin(314t+60) by observing the peak voltage determine following below calculate the form factor of the circuit a=1.87 b=1.59 c=1.11 d=1.48
- Find the phase and amplitude of the voltage on the inductance. C = 100uF L = 0.15H R =120 VR V. Vc I Vs 100V, 50HZThe attached image shows a circuit with an AC voltage source, a resistor, inductor, and capacitor connected in series. The circuit has the following characteristics: Resistor resistance: 10 ohm Capacitor capacitance: 0.05 F Inductor inductance: 13 H Current Amplitude: 4 A Voltage amplitude across the source: 60 V Frequency at the source: 0.3 Hz Voltage amplitude across the resistor: 35 V Voltage amplitude across the capacitor: 37 V Voltage amplitude across the inductor: 80 V (a) Calculate the RMS voltages from the amplitudes above. From the RMS voltages across the capacitor, inductor and resistor, calculate the RMS voltage of the AC source. Hint: Vrms = V0/sqrt(2) Vrms = sqrt( (Vrms,R)2 + (Vrms, L - Vrms, C)2 ) (b) Calculate the RMS value of the current (c) Using the resistance, capacitance, inductance, and the frequency of the AC voltage, calculate the impedance Z. From this, and the previously measured value of Vrms, find the RMS value of the current in the circuit.4. Find Idc, Vdc and the capacitance that will force the Vr(pp) to 2mV. Draw the output waveform across the capacitor. Fin=60HZ. TX1 D1 Ge Vac Lst 230V Lp 1 RL 12-0-12 Center tapped CL 1k D2 Ge 2
- The peak to peak distance of a sinusoidal waveform displayed on a C.R.O. screen is 7 cm and the 'volts/cm' switch is on 27 V/cm. The peak voltage is given by 3.86 V O 189.00 V O 94.50 V O 133.62 VIn a series LR circuit, the reactance of the inductance is 520 ohm. What will be the value of the inductor if the frequency of the AC is 60 HZ?Which of the following is true for pure capacitive circuit? O a. Current lags the voltage by 90 degree O b. Voltage lags the current by 90 degree O c. Voltage leads the current by 90 degree O d. Voltage and current are inphase