4) A projectile is fired with an initial speed (v) of 175 m/s, at an angle a of 30 degrees, and at a position 600 m above ground level. Based on Newton's 2nd Law and assuming no air resistance, the position vector of the projectile is: r(t) = (vecosa)ti + [ro+(vesina)t - 1/2gt²)]j where time t≥ 0, ro is the initial height above ground surface, and the acceleration of gravity g = 9.81 m/s². Where does the projectile hit the ground and with what speed?
4) A projectile is fired with an initial speed (v) of 175 m/s, at an angle a of 30 degrees, and at a position 600 m above ground level. Based on Newton's 2nd Law and assuming no air resistance, the position vector of the projectile is: r(t) = (vecosa)ti + [ro+(vesina)t - 1/2gt²)]j where time t≥ 0, ro is the initial height above ground surface, and the acceleration of gravity g = 9.81 m/s². Where does the projectile hit the ground and with what speed?
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.7: More On Inequalities
Problem 44E
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![4) A projectile is fired with an initial speed (v) of 175 m/s, at an angle a of 30 degrees, and
at a position 600 m above ground level. Based on Newton's 2nd Law and assuming no air
resistance, the position vector of the projectile is:
r(t) = (vecosa)ti + [ro+(vesina)t - 1/2gt²)]j
where time t≥ 0, ro is the initial height above ground surface, and the acceleration of
gravity g = 9.81 m/s².
Where does the projectile hit the ground and with what speed?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fabb75337-a8ce-4ff9-8c07-7d58c277bdaa%2Fc1a73c45-0de6-4fa4-8fd0-cfb4520ef217%2Fr3wlw89_processed.png&w=3840&q=75)
Transcribed Image Text:4) A projectile is fired with an initial speed (v) of 175 m/s, at an angle a of 30 degrees, and
at a position 600 m above ground level. Based on Newton's 2nd Law and assuming no air
resistance, the position vector of the projectile is:
r(t) = (vecosa)ti + [ro+(vesina)t - 1/2gt²)]j
where time t≥ 0, ro is the initial height above ground surface, and the acceleration of
gravity g = 9.81 m/s².
Where does the projectile hit the ground and with what speed?
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