3. One of the emission spectral lines for Be3+ has a wavelength of 253.4 nm for an electronic transition that begins in the n = 5 energy state. What is the principal quantum number of the lower energy state corresponding to this emission? AE = -7.8393x10-19 J Energy level, nF = 4

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter6: The Structure Of Atoms
Section6.7: One More Electron Property: Electron Spin
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3. One of the emission spectral lines for Be3+ has a wavelength of 253.4 nm for an electronic 29
transition that begins in the n = 5 energy state. What is the principal quantum number of the
lower energy state corresponding to this emission?
AE = -7.8393x10-19 J
Energy level, nf = 4
Transcribed Image Text:3. One of the emission spectral lines for Be3+ has a wavelength of 253.4 nm for an electronic 29 transition that begins in the n = 5 energy state. What is the principal quantum number of the lower energy state corresponding to this emission? AE = -7.8393x10-19 J Energy level, nf = 4
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