3. Here's a way to evaluate due to Euler. We've seen that sin 72 TZ - k² ·ÎI (¹-³). j=1 (a) Equate the coefficients of z² on both sides, to recover the desired sum. (b) Equate the coefficients of z4 on both sides to recover a different sum. By equating coefficients of higher powers of z, one can recover other identities too. On the next homework set we'll see a more general method to calculate sums.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.3: The Addition And Subtraction Formulas
Problem 71E
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3. Here's a way to evaluate
due to Euler. We've seen that
sin 72
TZ
-
k²
·ÎI (¹-²).
j=1
(a) Equate the coefficients of z² on both sides, to recover the desired sum.
(b) Equate the coefficients of z4 on both sides to recover a different sum.
By equating coefficients of higher powers of z, one can recover other identities too.
On the next homework set we'll see a more general method to calculate sums.
Transcribed Image Text:3. Here's a way to evaluate due to Euler. We've seen that sin 72 TZ - k² ·ÎI (¹-²). j=1 (a) Equate the coefficients of z² on both sides, to recover the desired sum. (b) Equate the coefficients of z4 on both sides to recover a different sum. By equating coefficients of higher powers of z, one can recover other identities too. On the next homework set we'll see a more general method to calculate sums.
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