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3. Fe and FeQ are in equilibrium with gas mixture of composition 71.8% CO-28.2%CO2 at 1273K. Which of the two solid phases disappears if the composition of the gas is held constant and temperature of the system is increased? Fe(s)+1/2O2(g)=FeO(s)_AG=-263700+64.35T C(s)+O2 (g)= CO2(g) AG=-394100-0.84T C(s) + 1/2O2 (g) = CO AG=-111700-87.65T

3. Fe and FeQ are in equilibrium with gas mixture of composition 71.8% CO-28.2%CO2 at 1273K. Which of the two solid phases disappears if the composition of the gas is held constant and temperature of the system is increased? Fe(s)+1/2O2(g)=FeO(s)_AG=-263700+64.35T C(s)+O2 (g)= CO2(g) AG=-394100-0.84T C(s) + 1/2O2 (g) = CO AG=-111700-87.65T

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section: Chapter Questions
Problem 71GQ: The equilibrium constant for the butane iso-butane equilibrium at 25 C is 2.50. Calculate rG at...
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3. Fe and FeQ are in equilibrium with gas mixture of composition 71.8% CO-28.2%CO2 at 1273K. Which of the two solid phases disappears if the composition of the gas is held constant and temperature of the system is increased? Fe(s)+1/2O2(g)=FeO(s) AG=-2 0=-263700+64.35T ammmm C(s)+O2 (g)= CO2(g) AG=-394100-0.84T C(s) + 1/2O2 (g) = CO AG=-111700-87.65T
Transcribed Image Text:3. Fe and FeQ are in equilibrium with gas mixture of composition 71.8% CO-28.2%CO2 at 1273K. Which of the two solid phases disappears if the composition of the gas is held constant and temperature of the system is increased? Fe(s)+1/2O2(g)=FeO(s) AG=-2 0=-263700+64.35T ammmm C(s)+O2 (g)= CO2(g) AG=-394100-0.84T C(s) + 1/2O2 (g) = CO AG=-111700-87.65T
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