3.Calculate the inclination of the hold section and the kickoff point for a horizontal well withthe following information:Apparent dip of the formation in the plane of the horizontal is 5º and the well is to drill updipBuild rate is 14%/100 feetBed thickness is 50 feetTVD of the target directly below the surface location is 4,000 feet4-39

Answered: Image /qna-images/answer/639eb692-d631-4d52-ba1e-e203c54dc5fa.jpg

3. Calculate the inclination of the hold section and the kickoff point for a horizontal well with the following information: Apparent dip of the formation in the plane of the horizontal is 5° and the well is to drill up dip Build rate is 14%/100 feet Bed thickness is 50 feet TVD of the target directly below the surface location is 4,000 feet

3. Calculate the inclination of the hold section and the kickoff point for a horizontal well with the following information: Apparent dip of the formation in the plane of the horizontal is 5° and the well is to drill up dip Build rate is 14%/100 feet Bed thickness is 50 feet TVD of the target directly below the surface location is 4,000 feet

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter19: Drilled Shaft

Section: Chapter Questions

Problem 19.10P

See similar textbooks

Similar questions

2. A 1" reading theodolite having a multiplying constant of 100 and an additive constant of 0 was centered and levelled a height of 1.48 m above a point C of reduced level 46.87 m. A levelling staff was held vertically at points D and L in turn and the readings shown in table 1 were taken. Calculate (i) the reduced levels of points D and L (ii) the horizontal length of DL. Staff position Staff reading (m) Vertical circle Horizontal circle D L 3.240, 3.047, 2.853 2.458, 2.230, 2.002 readings 87°38'53" 92°21'36" readings 56°49'31" 98°07'18"
In the two-peg test of a dumpy level, the following observations were taken. Rod reading at A Rod reading at B (m) (m) Instrument at pt. M 0.396 0.910 Instrument at pt. P 1.4 2.14 Point M is equidistant from both A and B, while point P is outside line AB, 2.5 meters from A and 79.27 m from B. *in the space provided, indicate: a. Find the difference in elevation between A and B. b. Adjust the correct readings when the instrument was at point P.
Complete solution pls. Tysm!
Problem1) Determine the depth to bedrock for a site. _______meters2) Determine the velocity of the overburden _______meter/second and3) Determine the velocity of the bedrock _________meter/second.4) Critical distance from the source point __________metersGeophone 1 is 20 meters from the shot point and each geophone is 20meters from the next one.Geophone First Arrival time (seconds)1 0.0152 0.0313 0.0464 0.0625 0.0776 0.0897 0.0948 0.0999 0.10510 0.11011 0.11512 0.121
Compute the critical effective area between staggered failure paths for the channel bar shown if the gross area is 7,000mm2 and the channel's thickness is 20mm. The diameter of the boit holes used in this connection is 25mm 55mm 75mm 65 40 50 80 75 60. mm mm mm mm mm mm
1. The following are factors considered in assigning factor of safety due to consequences of failure except a. Variation in the strength of materials purchased b. Direct cost of clearing the debris c. Replacing the structure and its contents d. None of the choices 5. Calculate the depth of neutral axis at balanced condition if the effective depth is 250 mm and fy is 415 MPa. a. 147.78 mm b. 212.50 mm c. 294.12 mm d. 223.25 mm 6. Calculate the stress at the centroid of the tension steel in single layer if the effective depth is 250 mm and the depth of neural axis is 100 mm. a. 800 MPa b. 500 MPa c. 1000 MPa d. 900 MPa 7. Calculate the strain at the centroid of the tension steel in single layer if the effective depth is 250 mm and the depth of neural axis is 100 mm. a. 0.0040 b. 0.0025 c. 0.0050 d. 0.0045
10 A theodolite was set up near the middle of the points "P" and "Q". If the height of the instrument is 1.20 m. The rod is sighted at point "P", vertical angle = +24 degrees, rod reading = 1.3 m, and stadia interval = 1.4 m. Then the rod is sighted at point "Q", vertical angle = +23 degrees, rod reading = 1.6 m, and stadia interval = 1.1 m. Taking K = 100, and C = 0. a) Horizontal Length from Point "P" and "Q" 210.045 m 216.829 m 219.837 m 225.013 m 213.560 m None of the Choices 222.570 m
What is the elevation (ft) of the lower station with the following conditions? (Answer with two decimal places.) hi ● 2+72.32 α S wire Rod R.R. • Elevation of Station 2 + 72.32 is 365.85ft • The theodolite's optical center (hi) is 4.25ft above the upper baseline station at 2 + 72.32 • Vertical angle a is 30 degrees Slope distance (S) is 81.15ft • Rod reading (R.R.) at the lower station is 4.15ft
6 A theodolite was set up near the middle of the points "P" and "Q". If the height of the instrument is 1.20 m. The rod is sighted at point "P", vertical angle = +24 degrees, rod reading = 1.3 m, and stadia interval = 1.4 m. Then the rod is sighted at point "Q", vertical angle = +23 degrees, rod reading = 1.6 m, and stadia interval = 1.1 m. Taking K = 100, and C = 0. b) Difference in elevation between Point "P" and "Q" 12.756 m 9.362 m 6.401 m 1.881 m 5.731 m 2.169 m None of the Choices
Solve and show compleete solution.A theodolite is set up at point A and a subtense bar mounted on a tripod set up on point B. The instrument sighted the leftmost end of the subtense bar and the initial reading is 0°15’14”. The surveyor turned the theodolite clockwise and sighted the rightmost end of the subtense bar and the final reading is 1°51’05”. What is the distance between point A and B?. (The angle between 2 lines is the difference of the final and initial reading)
QL: Determine the vohume of earthwork to be excavated for the plot shown in fig 1. The formation level is 69.00 m. 1t o i T ne no nn na 15m n o) g g t5m 7 710 e T Figure 1
1. Well is being drilled with following assembly Ea BHA jt 30.5 Ft Ea DP Stand 93.5 ft TDS + Hook block = 68 K Lbs %3D Depth is 12800 Ft, Mud weight is 86 Pcf 1. Bit 2. Bit sub 3. 91 2" x 3" DC 9 Jts 4. 8 %" x 3" DC 3 Jts 5. 6" 2%" dc 6 Jts 6. 5 %" HWDP 15 Jts 75 PPF 7. 5 " G105#324.7 DP 105 Stands 8.5" S135 #24.7 DP to Surface a. What is the hook load b. How much Max weight on Bit can be given