3. (37%) A tank is separated into two volumes by an insulated frictionless massless piston. The upper volume is insulated and contains 0.5 kg of Argon (mole. wt=40) that is initially at 20°C. 150 kPa. The lower volume is initially evacuated and has an initial volume of 0.1 m³. The valve is then opened, and left open, and 197°C, 500 kPa air from an insulated pipe fills the lower volume and compresses the argon; the compression of the argon is internally isentropic and polytropic. There is an amount of heat transfer between the air in the tank and the surroundings at 27°C such that the final temperature of the air in the tank is 37°C. The air is to be treated as an ideal gas with variable specific heat. a) b) What is final temperature of the argon (K)? What are the initial and final volumes of the argon (m³)? What is the work for the argon compression (kJ)? What is the final mass of air in the tank (kg)? What is the amount of heat transfer (kJ)? What is the entropy generation for the tank (kJ/K)? Argon Air that enters To=27°C Q Yolve she T=20°c ; P=150 kPa T₂ = 147°C P=500kPa Air pipe, T 197°C, 500 kPa PV=MFT (a) Qar =@ema - Khair 5.-1.5 0 = 5° (12) -5° (7) -Rin 5= MW System: Argun! 4U-A-W 3 12. u = f(<) h=f/T) Save S= s' RI 5° (T.) - Rin Pref S =

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Question
How do I solve this thermodynamics practice test problem, I don’t know what I’m doing lol
3. (37%) A tank is separated into two volumes by an insulated frictionless massless piston. The
upper volume is insulated and contains 0.5 kg of Argon (mole. wt=40) that is initially at 20°C.
150 kPa. The lower volume is initially evacuated and has an initial volume of 0.1 m³. The valve
is then opened, and left open, and 197°C, 500 kPa air from an insulated pipe fills the lower
volume and compresses the argon; the compression of the argon is internally isentropic and
polytropic. There is an amount of heat transfer between the air in the tank and the surroundings
at 27°C such that the final temperature of the air in the tank is 37°C. The air is to be treated as an
ideal
gas with variable specific heat.
a)
b)
What is final temperature of the argon (K)?
What are the initial and final volumes of the argon (m³)?
What is the work for the argon compression (kJ)?
What is the final mass of air in the tank (kg)?
What is the amount of heat transfer (kJ)?
What is the entropy generation for the tank (kJ/K)?
Argon
Air that enters
To=27°C
Q
Yolve she
T=20°c
;
P=150 kPa
T₂ = 147°C
P=500kPa
Air pipe, T 197°C, 500 kPa
PV=MFT
(a)
Qar =@ema - Khair
5.-1.5
0 = 5° (12) -5° (7) -Rin
5=
MW
System: Argun!
4U-A-W
3
12.
u = f(<) h=f/T)
Save
S= s' RI
5° (T.) - Rin Pref
S =
Transcribed Image Text:3. (37%) A tank is separated into two volumes by an insulated frictionless massless piston. The upper volume is insulated and contains 0.5 kg of Argon (mole. wt=40) that is initially at 20°C. 150 kPa. The lower volume is initially evacuated and has an initial volume of 0.1 m³. The valve is then opened, and left open, and 197°C, 500 kPa air from an insulated pipe fills the lower volume and compresses the argon; the compression of the argon is internally isentropic and polytropic. There is an amount of heat transfer between the air in the tank and the surroundings at 27°C such that the final temperature of the air in the tank is 37°C. The air is to be treated as an ideal gas with variable specific heat. a) b) What is final temperature of the argon (K)? What are the initial and final volumes of the argon (m³)? What is the work for the argon compression (kJ)? What is the final mass of air in the tank (kg)? What is the amount of heat transfer (kJ)? What is the entropy generation for the tank (kJ/K)? Argon Air that enters To=27°C Q Yolve she T=20°c ; P=150 kPa T₂ = 147°C P=500kPa Air pipe, T 197°C, 500 kPa PV=MFT (a) Qar =@ema - Khair 5.-1.5 0 = 5° (12) -5° (7) -Rin 5= MW System: Argun! 4U-A-W 3 12. u = f(<) h=f/T) Save S= s' RI 5° (T.) - Rin Pref S =
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