3 kN 30° 0.1 m 0.1 m -0.2 m -0.3 m- 5 kN 4 kN (a)

Q: 1. Analyze the frame. 2W(kN/m) 3W(KN) 1m 3m 1m 2m 4W(KN) '60°

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Q: 60 kN/m- 30 kN/m A Hinge B 5 m 10 m-

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Q: Calculate the member forces of the loaded structure. y 60 kN D 40 kN 7 m C, 3 m Ax Ay -4 m-

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Q: Replace the three forces and one couple which act on the bar by a force-couple system at the support…

A: Equilibrium of horizontal forces, ∑Fx=0Fx=5cos45°=3.54 kN Equilibrium of vertical forces,…

Q: Solve the value of Ely 1m from the free end. 6 kN 2 kN/m 4 kN A -1.5 m--1.5 m- m -3m- O-28.92kNm^3 B

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Q: Determine the vertical reaction at point B. Round off your answer to whole number. 200 kN 25 kN/m A…

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Q: 5 kN 20 kN/m B. -2 11 3m

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Q: Bo0 Deter mine the N 200 magni mde and direction of the resultant 300 of the four forces shown in…

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Q: Q1-B- Draw just the Free Body Diagram of the following figures. 30 kN/m Fig. (2) B C -3 m Fig. (4) 4…

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Q: 12 kN/m 3 m Hinge 5 m 4 m- -4 m-

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Q: Reaction at A and c? 9 kN/m 3 m -3 m

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Q: Determine Ely at the midspan of the beam. 50 kN Wo= 10 kN/m 2 m D 2 m 4 m A

A: To find the deflection at any point first calculate reactions on supports. The divide beams into…

Q: Draw the FBD. Then, determine the reactions at A and B. 650 N 500 N 30° 300 N 1500 N m 60° B -3 m -5…

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Q: 3. Determine the value of Ely at the end E of the overhanging beam. El is constant. 50 kN 10 kN A D…

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Q: Refer to the shear diagram shown -5 kN 10 kN -10 kN -15 kN -1 ml-2 m-42 m- Which of the following…

A: Given Shear force diagram and it is asked to find maximum bending moment in the span.

Q: B 4.5 m. 1.5 m

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Q: 29 kN/m Hinge 14.5 kN/m 3 m 3 m 14.5 kN/m 29 kN/mHinge Hinge 3 m - 5 m 5m

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Q: BEAM 3 Assume support B settles 25mm downwards.

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Q: 24 kN S KN/m D 3m- 3m→-3m

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Q: 2 Compute the internal reaction of member DG of the truss. F D B = 60 KN 80 KN 14 m B A J 4 m C 4 m…

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Q: Replace the loading by an equivalent resultant force and couple moment acting at point O.

A: The given figure can be divided into three parts as shown below.

Q: Hydrostatic force acting on the wall. .The resisting moment of the dam to overturning in kN-m. -…

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Q: SITUATION. For the Beam as shown. 5 kN-m D 6m 4m Determine the Reaction at A 0.333 kN 0.456 kN 0.667…

A: Since only nodal forces are acting calculate the moment resisted by member CA. This can be evaluated…

Q: Q2 Replace the distributed loading by an equivalent resultant force and couple moment acting at…

A: From the above diagram F1 = 12×3×3⇒F1 = 4.5 KNF2 = 6×3⇒F2 = 18 KNF3 = 12×3×3⇒F3 = 4.5 KN

Q: 100 KN 10 kN/m Com 21 12m I E = constant %3D

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Q: Dertermine the following: 1. Slope at A 2. Reaction at B 3. Slope at C 4. Deflection at D. 5.…

A: Given data: E=200 GPaI=500×106 mm4EI=200×106×500×10-6EI=100000 kN.m2

Q: F2-10. Determine the magnitude of the resultant force of the water acting on the triangular end…

A: Please refer the attached image for complete solution. THANK YOU.

Q: The end of the boom O is subjected to three concurrent and coplanar forces. Determine the magnitude…

A: Schematic diagram of the given problem:

Q: In the link (10 kg) below at time = 0 seconds, the rotational velocity of the link is zero and theta…

A: The angular velocity of the system after 3 revolutions is, θ=3×2πθ=6π  radians The time taken is,…

Q: What is the degree of static indeterminacy of the structures shown? M. 2m 2m pan cdor ro dilio…

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Q: Determine the maximum shear (kN) in the given structure. 10 kN 5 kN 5 kN IB 2 kN/m 4 m A. -3 m- 2…

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Q: Find the support reactions 50 KN/m 20 KN/m 4m 2m--

A: Following is the given beam:   Note: The total load is divided into a triangular and a rectangular…

Q: 1. Neglecting friction and the weights of the members, compute the magnitudes and directions of the…

A: The FBD of the table is shown below: Taking equilibrium equation:

Q: Determine the Support reaction at A And B? 4m w=15 kN/m ↓ A OB IC

A: Given :

Q: 20 kN 4 kN/m 5 kN-m CO 6 m 10 m 5 m

A: This is a case of a propped cantilever beam with an internal hinge so become a determinate beam.

Q: Solve the value of Ely 1m from the free end. 6 kN 2 kN/m 4 kN A 3 m -1.5 m 1.5 m

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Q: 5 kN 20 kN/m B C A D 0000 -2 m² 3 m 1 m

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Q: Draw the FBD. Then, determine the reactions at A and B. 650 N 500 N 30° 300 N 1500 N m A 60° B -3 m…

A: Draw the FBD. Then, determine the reactions at A and B.

Q: The compound beam is pin supported at A and supported by a roller at B and D. There is an internal…

A: Hello dear this is the solution of your problem The answer is found to be a.Reaction at…

Q: The unstretched length of spring AB is 3 m. If the block is held in the equilibrium position shown,…

A: to find mass of block D

Q: Replace the distributed loading by an equivalent resultant force and couple moment acting at point…

A: The given figure is shown below:

Q: Required : Support Reactions ( Ma, Av, By, Cy) 45 kN 20k/m 90 kN.m 28 2m 2m 4m

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Q: II. Find the reaction forces. A 40 KN/m 12 m 75 KN-m 3 m ↓ 3 m 20 KN/m 6 m B

A: Given data  Find the support reaction forces.

Q: Replace the force system by an equivalent resultant force and couple moment at point B. 6 kN/m 15 kN…

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Q: The end of the shown boom O is subjected to three concurrent and coplanar forces. Determine the…

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Q: 2.0 m Zoom image Determine the vertical reaction at C. 0.8 m E +0.9 m-0.9 m- W=5.4 KN 0.4 m

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Q: 15 kN Find the support 10 kNm 5 kN/m reactions of the 1 m 20 kN structural ssytem. 5 kN/m 1,5 m 30…

A: Given:-

Q: Determine the couple moment acting on the beam. 10 kN 5 4 m A Im 10 kN

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Q: 1. The beam is subjected to a load F = 400 N and is supported by the rope and the smooth surfaces at…

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Q: 10 kN upward 10 kN, downward 50 kN upward 50 kN downward 5 kN/m -2 m- M = 60 kN m -2 m-1m-

A: The Given loading is shown on a cantilever beam. Cantilever beam is a statically determinate beam so…

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.