3 ka 470 k2 R, 10 uF 20 µF B = 100 0.3 k2 + 4.7 k2 Z.
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Determine Av=Vo/Vi. If the two-port parameters for the fixed-bias configuration are Zi =1.071 KΩ, Zo=3 KΩ, and AvNL= -280.11.
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- Capacitive Circuits Fill in all the missing values. Refer to the formulas that follow. XC=12fCC=12fXCf=12CXc Capacitance XC Frequency 38 F 60 Hz 78.8 400 Hz 250 pF 4.5 k 234 F 10 kHZ 240 50 Hz 10 F 36.8 560 nF 2 MHz 15 k 60 Hz 75 nF 560 470 pF 200 kHz 6.8 k 400 Hz 34 F 450+5V VDO EN Xtal 8ה 7 +5V Freq1 HGND | GND х Mhz Sensor0 crystal Freq26 5 Vss Out 04 PRE Xtal 1k Output HA7210IP 4 CLK CLR SN74HC7491 GND 0.01 μ GND +5V 4 +5V +5V +5V OE O/P3 0. 1µF | 47µF GND SG351P |2 x MHz GND GND Consider the Quartz Crystal Microbalance Sensor shown above, with crystal resonant frequency, x = 3.3 Mhz. You are given the following values: Active crystal area = 1.6 cm², and the change in frequency = - 10 Hz Calculate the change in mass, Am in nano gram, up to 2 decimal places. Answer:Find T 0.5 ms 40 92 www www 892 160 92 20 mH www
- Discussion For the circuit below complete the table R 5Ω 10 V 60 Hz 100 μF R Total 10+j0 Volts 10 Z0° 68.623m +j364.06m Amps 370.5m Z 79.325° 5+ j0 0- j26.5258 5 - j26.5258 Ohms 520° 26.5258 -90° 26.993 Z-79.325°444 mH b 720 mH 90 mH 60 mH 240 mH 20 mH (a) HE 80 nF 8 nF 10 nF 48 nF 20 nF b не (b)Q5] find the current of the resistance 1892 if the value of the source is 7.4sin(100πt-44) volt HH 1mF R1 ww 18Q R4 •14Ω 3.9mF 13.100, 78.163⁰ mA O 14.100, 78.163⁰ mA O 15.100, 78.163⁰ mA 0.093H V1
- Electrical Engineering 6/0° v j1 N V1 V2 1Ω 1 Ω -j1 N= 2/0° A find lowww H 0.47μF 14 V 68 ΚΩ 10 ΚΩ 1.2 ΚΩ Cwi Cwo 5.6 ΚΩ = 5 pF = 8 pF 0.47 μF HH B = 120 20 μF Cbc = 12 pF Cbe= 40 pF Cce = 8 pF V₂ 1. 3.3 ΚΩ a. Determine re- b. Find Avid Vo/Vi- = c. Calculate Z₁. d. Determine fife and fle e. Determine the low cutoff frequency. f. Determine fH, and fH.Question 13 For the circuit shown, the following mesh currents are given: IA =1.24271.2° A IB =0.45Z49.0° A Ic = 0.75Z150.2° A What is the value of the voltage VB? j5n + 20 VB 62- 45° V j4 N VA 240° V Vc 5230° V O 2.484- 108.8° V O 2.48471.2 V O 2.23/66.8° V O 2.23Z- 113.2° V
- Discussion For the circuit below complete the table R 5Ω 10 V 60 Hz 100 µF R C Total 10 + j0 V Volts 10 Z0° 68.623m + j364.06m Amps 370.5m Z 79.325° 5+ j0 52 0° 5 - j26.5258 26.993 Z-79.325° 0 - j26.5258 Ohms 26.5258 Z-90°5 mH 60 is = 50 Cos (314 t+30) A 1 mF Figure Q1(a)Given the circuit below, please find the current 12 O 1.33A 13.33A 6.66A 0.66A 20 A R₁ < 50 ΩΣ R₂ 100 ΩΣ