Need help with #2 2)The circuit on the right must be solved using Kirchhoff's rules.Current /i flows through the branch containing R1, V1 and Rs.Current /2 through the branch containing R2, V2, and R4.Current Is flows through the branch containing V3 and Is,R1 = 40R2 = 32A) Apply Kirchhoff's Junction Rule, Choose a node, and indicatethe direction of current flow in/out. Write the--V = 9VV2 = 12Vappropriate equation.at Nede a: )-Y)-0"ナV3 = 6VR4 = 3242+Rs = 42-B) Choose one loop and apply Kirchhoff's Loop Rule.Clearly identify which loop you are analyzing, and write theappropriate equation.A Nede mC) Choose a second, different loop, and apply the Loop Rule once more. Again, clearly identify which loopyou are analyzing, and write the appropriate equation,R33D20

It states that in any complete loop within a circuit, the sum of all voltages across components…

2)The circuit on the right must be solved using Kirchhoff's rules. Current /i flows through the branch containing R1, Vi and Rs. Current /2 through the branch containing R2, V2, and Ra, Current /s flows through the branch containing Vs and h. R1 = 42 R2 = 30 y - A) Apply Kirchhoff's Junction Rule, Choose a node, and indicate the direction of current flow in/out. Write the appropriate equation, !=V = 9V V2 = 12V V3 = 6V R4 = 32 42 +Rs = 42- %3D R3=2N

2)The circuit on the right must be solved using Kirchhoff's rules. Current /i flows through the branch containing R1, Vi and Rs. Current /2 through the branch containing R2, V2, and Ra, Current /s flows through the branch containing Vs and h. R1 = 42 R2 = 30 y - A) Apply Kirchhoff's Junction Rule, Choose a node, and indicate the direction of current flow in/out. Write the appropriate equation, !=V = 9V V2 = 12V V3 = 6V R4 = 32 42 +Rs = 42- %3D R3=2N

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter10: Direct-current Circuits

Section: Chapter Questions

Problem 94CP: Consider the circuit below, (a) What is the initial current through resistor R2? when the switch is...

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