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- In a three point cross problem for genes Q, L, and T, you have identified the parentals and double recombinants. Using that data (shown below), what is the order of the genes? Type: Alleles parental q L t parental Q l T double cross over q L T double cross over Q l t Group of answer choices L Q T L T Q T L Q the correct answer is not availablePurple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口 ロ口A recessive epistasis cross gives in the F2 a 9:3:4 phenotypic ratio. What is the expected phenotypic ratio when the F1 (BbEe) is crossed with the double recessive homozygote (bbee)? Keeping in mind ee masks the expression of B.
- White fruit color in summer squash is dependent on a dominant gene (W) and colored fruit to the recessive gene (w). In the presence of ww a dominant gene D produces yellow color, but when D is not present, the color is green. Upload your solution in the google classroom. Give the: F1_phenotypes_expected_from_crossing_white_fruited_WWDD_with_green_fruited_wwdd_plant F2_phenotypes_expected_from_crossing_the_F1 F2_phenotypic_ratio_expected_from_crossing_the_F1 F2_genotypic_ratio_expected_from_crossing_the_F1 Type_of_epistatis Write all phenotypes in CAPITAL letters SEPARATED BY COMMA. Write all ratio in numerical values without spacesIn sweet pea plant, an allele for purple flowers (P) is dominant when paired with a recessive allele for red flowers (p). An allele for long pollen grains (L) is dominant when paired with a recessive allele for round pollen grain (l). Bateson and Punnett crossed a plant having purple flowers/long pollen grains with one having white/flowers/round pollen grains. All F1 offspring had purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes: 296 purple flowers/long pollen grains 19 purple flowers/round pollen grains 27 red flowers/long pollen grains 85 red flowers/round pollen grains What is the best explanation for these results?Please consider the pedigree below. There are no cases of false paternity. I II III IV в 1 a. Which individual/s definitely has/have Bombay phenotype in the descendants of I-1 and I-2? b. What are the genotypes of individuals II-2 and III-2 at the AB0 and H loci? Please label your answers a and b, Il-2: and Ill-2:.
- Here are the progeny of this cross: (Note that the categories are not in any particular order.)Fly type # of prog. Phenotype symbols Categorywt eyes black body wt wings 97 grn+ blk crv+Green eyes black body curved wings 709 ParentalGreen eyes wt body wt wings 9Green eyes black body wt wings 162wt eyes wt body wt wings 727wt eyes black body curved wings 12wt eyes wt body curved wings 179Green eyes wt body curved wings 105Total = 2000 9.) Write the phenotype symbols in the right-hand column. The first one has been done for you.10.) Next to that, label all fly categories as parental (NCOs), SCOs, and DCOs. One has been donefor you.11.) After each SCO/DCO label, write which gene got “unlinked” in these offspring.12.) Put these three genes into a genetic map in the proper order.13.) Calculate the genetic distance between the genes and label the map with these distances.14.) Calculate the cross-over interference15.) Return to questions #1-6 above. For question 6, you gave your opinion, but…For each genotype, indicate whether it is heterozygous (HE) or homozygous (HO) AA Bb Cc Dd Ee ff GG HH PP Pp pp Round seeds are dominant to wrinkled RR Rr rr Ii Jj kk For each of the genotypes below, determine the phenotype. Purple flowers are dominan to white flowers L1 Mm nn straight straight curly 00 Pp Brown eyes are domin BB Bb bb to blue eyes Bobtails are recessive (long tails dominant) TT Tt tt For each phenotype, list the genotypes. (Remember to use the letter of the dominant trait) Straight hair is dominant to curly. Pointed heads are dominant to round heads. pointed pointed roundNotation: D = disease allele at gene d = wild-type allele at gene Let’s provide some information about each MOI. AD: Each of the F1 parents is heterozygous for the D allele. SLR: The observed F2 data are the offspring from an F1 cross where the father is affected (disease) and the mother is an unaffected carrier (wild-type, or WT). That is, the mother’s genotype has one disease allele and one WT allele in it. In Table 1, I provide the observed data counts (in dark blue). Notice that I stratify by gender. Table 1 Phenotype O E O-E (O-E)^2 (O-E)^2 /E Disease, Male 304 Disease, Female 267 WT, Male 285 WT, Female 301 Total 1157 DF p-value In Table 2, provide expected proportions for two different MOIs: AD and SLR. The values in this table are computed using information from the Punnett Square and the specified MOI. Once the proportions are determined, we can fill in the values in Table 3, E(xpected)…
- 6 5 0/1 point Let's continue with these two genes that control the color and texture of tomatoes. Allele "R" generates a red coloration, and is dominant. Allele "r" generates a green col Allele "S" generates a smooth texture, and is dominant. Allele "s" generates a rough te You now decide to cross your dihybrid RrSs but this one with a tomato with Rrss. RrSs x Rrss What is the probability of getting Red tomatoes with Rough texture in this new cro Assume complete dominance and 100% penetrance and expressivity. O 1/8 3/16 O9/16 3/8 O 1/16 X x 1/4 1/2 1/1 point Later on, you made a completely new cross. But you cannot remember the ge You are sure that one parent was (Ww). You remember your Bio class back in VCU and decided to check the ratios in If this cross (Ww X ??) produced 140 plants, and 105 have purple flowers anIn a diploid plant species, an F1 with the genotype Gg Ll Tt is test-crossed to a pure-breeding recessive plant with the genotype gg ll tt. The offspring genotypes are listed in the table. Genotype Number Gg Ll Tt 621 Gg Ll tt 3 Gg ll Tt 64 Gg ll tt 109 gg Ll Tt 103 gg Ll tt 67 gg ll Tt 7 gg ll tt 626 1600 Calculate the recombination frequency between G and T pair of genes. A. 0.227 B. 0.139 C. 0.454 D. 0.233Example: Linkage - Drosophila Body Color / Eye Color Please choose two parent genotypes of dissimilar gender by dragging them into the parent cells at right. Then select check boxes to identify nonrecombinent and recombinent offspring. Click the clear button if you would like to start over. Xy+w+ xyw Xyw y (Xy+W+ хуш) (XyW+ xy+W) (Xyw y) Nonrecombinent phenotypes: Nonrecombinent genotype: Recombinent genotype: Female/males with gray body/red eyes; females/males with yellow body/white eyes. Female/male with gray body/white eyes; female/male with yellow body/red eyes. Female/male with gray body/white eyes; female/male with yellow body/red eyes. Female/male with gray body/red eyes; female/male with yellow body/white eyes. Clear Recombinent phenotypes: Help Xy+w+ xyw Xy+w xyw XyW+ xyw Xyw xyw Xy+w+y Xy+wy XyW+ y Xyw y Submit