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28. Balance the equation for the reaction, using no fractional coefficients. ? Cr₂O3 + ? KOH +? O₂ → ? K₂CrO4 + ? H₂O The coefficient of KOH in the balanced equation is (A) 2 (B) 4 (C) 6 8 (E) 10 (D) (D)

28. Balance the equation for the reaction, using no fractional coefficients. ? Cr₂O3 + ? KOH +? O₂ → ? K₂CrO4 + ? H₂O The coefficient of KOH in the balanced equation is (A) 2 (B) 4 (C) 6 8 (E) 10 (D) (D)

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter3: Equation, The Mole, And Chemical Formulas
Section: Chapter Questions
Problem 3.38QE
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28. Balance the equation for the reaction, using no fractional coefficients. ? Cr₂O3 + ? KOH +? O₂ → ? K₂CrO4 + ? H₂O The coefficient of KOH in the balanced equation is (A) 2 (B) 4 (C) 6 8 (E) 10 (D) (D)
Transcribed Image Text:28. Balance the equation for the reaction, using no fractional coefficients. ? Cr₂O3 + ? KOH +? O₂ → ? K₂CrO4 + ? H₂O The coefficient of KOH in the balanced equation is (A) 2 (B) 4 (C) 6 8 (E) 10 (D) (D)
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