22 A consumer is supplied at 380V 3 phase from a 11 kV substation through a 1500 kVA 11kV/380V transformer and a 380V cable as shown in Fig. Q2. An overcurrent relay supplied through a 3000/5 C.T. is installed at the low voltage side of the transformer t protect the cable and the consumer. The fault level of the 11kV substation is 250 MVA The impedance of the transformer and the 380V cable are shown in Fig. Q2. i) Calculate the maximum fault current which the relay will be expected to measure fo any type of fault in the 380V system. 1500 KVA 11KV/380 V 3000/5 MVAse 250 MVA 1x₁-x₂=X₂-5% 2₁-2₂ -0.005 +10.005 Zo-0.01 +10.005 380 V I

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22
A consumer is supplied at 380V 3 phase from a 11 kV substation through a 1500 kVA
11kV/380V transformer and a 380V cable as shown in Fig. Q2. An overcurrent relay
supplied through a 3000/5 C.T. is installed at the low voltage side of the transformer to
protect the cable and the consumer. The fault level of the 11kV substation is 250 MVA.
The impedance of the transformer and the 380V cable are shown in Fig. Q2.
i) Calculate the maximum fault current which the relay will be expected to measure for
any type of fault in the 380V system.
MVAse 250 MVA
II
1x₁-x₂=X₂-5%
Z₁-Z₂-0.005 +10.005
Zo 0.01 +0.005
11 XV
1500 KVA
11 kV/380 V
3000/5
Fig. Q2
380 V
Transcribed Image Text:22 A consumer is supplied at 380V 3 phase from a 11 kV substation through a 1500 kVA 11kV/380V transformer and a 380V cable as shown in Fig. Q2. An overcurrent relay supplied through a 3000/5 C.T. is installed at the low voltage side of the transformer to protect the cable and the consumer. The fault level of the 11kV substation is 250 MVA. The impedance of the transformer and the 380V cable are shown in Fig. Q2. i) Calculate the maximum fault current which the relay will be expected to measure for any type of fault in the 380V system. MVAse 250 MVA II 1x₁-x₂=X₂-5% Z₁-Z₂-0.005 +10.005 Zo 0.01 +0.005 11 XV 1500 KVA 11 kV/380 V 3000/5 Fig. Q2 380 V
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