21. Express the force vector, F, shown in Figure 2 in Cartesian form. a. (-10+10) lbf b. (8.675.00ĵ) lbf c. (-5.00+ 8.67ĵ) lbf d. (-8.67+5.00ĵ) lbf e. (-5.00-8.67ĵ) lbf y F = 10 lbf 30° Figure 2 7
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- 20. The potential energy of a 40-kg cannon ball is 14000J. How high was the cannon ball to have this much potential energy?Answer provided. answer should be A.)6.75J,B.)2.03m/s Please show your complete solution and write clearly. Thank you.6. Always begin by writing the general form of an equation. Insert numbers and units. Remember to show all work (and units). Present the solution well organized and clearly. answer should be: |???⃗⃗⃗⃗⃗⃗|=185??/ℎ,?=22.3°,????ℎ ?? ???? just need an explanation on how to get to this.
- In the figure shown, if the mass (m=7 Kg) is moving with constant speed and traveled a distance d=10 m, what is the work done in Joules by frictional force? Given that F =11 N and 0 =53 °. m А. —66.2 B. None С. — 198.6 D. – 264.8 Е. — 132.44. Consider a lightbulb rated for a power of 20 watts. This lightbulb consumes a certain amount of electrical energy in 1 second of use. Suppose we want to generate the same amount of energy by dropping from height to ground level. If the mass of the lightbulb Is 0.050 kg, what is h or the height?D. None of the above 10. How much potential energy does a car gain if a crane lifts the car with a mass of 1,500 kg, 20 m straight up? A. 2.94 k] B. 2.94x102 kJ C. 294J D. 294 000 kJ
- 6. Engines, including car engines, are rated in horsepower. What is horsepower? The force needed to keep the engine running at a steady rate. b. The energy the engine needs to obtain from gasoline or some other source. The rate at which the engine can do work. d. The amount of work the engine can perform. а. с.What is the number of latitude degrees between place A (50N, 90W) and place B (60S, 90E)?Find the simplest unit of the Q = va/w , in which v is velocity, a is acceleration and w is work. a. 1/m.s b. 1/kg.s C. m.s d. 1/kg.m
- 4. Always begin by writing the general form of an equation. Insert numbers and units. Remember to show all work (and units). Present the solution well organized and clearly. answer should be: a) F=566N, FN=1.13x103N just need an explanation on how to get to this.You leave your car in a parking garage 46.5 ft above the ground. If your car weights 3400 lbf, what is the change in the car's gravitational potential energy? Express this quantity in units of calories.A truck is carrying 1.35 tonne of calcium carbonate to a sugar industry located on top of the hill. Calculate the weight of truck, if it gains potential energy of 689kJ at half the way of its journey to 25m height hill. O 2.09 kl s?/m? O 0280 kl s?/m? O 5618.75 kg O 2809.37 kg