Need help 21. Considering the pedigree of recessive inheritance in Figure below and taking into accountthe fact that individual IV-1 is not allected, what is the probubility that IV-1 is beterozygous?One of theseporsons is heterozygoun.HeterozygousIVHomorygousrecessiveMating betweenfirst cousinsA. 0.5B. 0.33C. 0.2D. 0.25E. 0.1

Pedigree is a family tree or chart made of symbols and lines that represent the genetic history of a…

21. Considering the pedigree of recessive inheritance in Figure below and taking into account the fact that individual IV-1 is not allected, what is the probability that IV-1 is heterozygous? One of these persons is heterozygous Heterozygous IV Homozygous recessive Mating between first cousins A. 0.5 B. 0.33 C.0.2 D. 0.25 E. 0.1 旺:

21. Considering the pedigree of recessive inheritance in Figure below and taking into account the fact that individual IV-1 is not allected, what is the probability that IV-1 is heterozygous? One of these persons is heterozygous Heterozygous IV Homozygous recessive Mating between first cousins A. 0.5 B. 0.33 C.0.2 D. 0.25 E. 0.1 旺:

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter12: Mendel, Genes, And Inheritance

Section: Chapter Questions

Problem 7TYK: In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene...

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1. 4. 6. Which mode(s) of inheritance could be RULED OUT for this smaller version of the previous pedigree? Does X-linked recessive fit the pattern? 5.
26. The trait represented in the following pedigree is expressed only in the males of the family. Is the trait Y linked? Why or why not? If you believe that the trait is not Y linked, propose an alternative explanation for its inheritance. 1 2 II 3 6 II I 2 3 4 5 6 7 8 IV 1 2 Pierce, Genetics: A Conceptual Approach, 7e © 2020 W. H. Freeman and Company
BIU A- == 三E 12 - Match each of the following examples to the appropriate type of non-Mendelian inheritance. 1. A homozygous recessive genotype for the gene that encodes phenylalanine hydroxylase (which breaks down the amino acid phenylalanine) causes lighter skin color, a musty odor, differences in intellectual development, and seizures. 2. In pea plants, alleles of Gene W control flower color, with the dominant allele (W) leading to purple flower.color, and the recessive allele (w) leading to white flower color. Usually, a genotype of WW or Ww leads to purple flowers. However, when Gene C is homozygous recessive, WW or Ww plants always have white flowers. 3. In mallard ducks, feather coloring is controlled by Gene F. A dominant allele (F) leads to green head feathers, while a recessive allele (f) leads to brown head feathers. In male mallards, inheritance of one or more F alleles always leads to the green head feather trait. But female mallards always have brown head feathers,…
3:48 1 Drive Multiple genes or polygenic inheritance: An additive effect of two or more genes on a single phenotypic character. 16. Skin color appears to be controlled by several genes. This creates a continuum of variation) also seen in height, hair color, etc.) If this polygenic explanation of the inheritance of human skin pigmentation is correct, how do the skin colors of the following four individuals compare? Which of the couples could have children with the widest range of skin colors? Why? Couple 1: aaBbCC and aaBbCC Couple 2: AaBbCc and AaBbCc Lethal Genes: An allele that if present, results in premature death. Lethal genes can be either dominant (heterozygotes or homozygous dominant will be affected) or recessive (only homozygous recessive will die). 17. When Mexican Hairless dogs are crossed with normal-haired dogs, about half of the puppies are normal (have hair) and half are hairless. When two Mexican hairless dogs are crossed, about 1/2 of the puppies are hairless, 1/4…
3) The most likely inheritance pattern in the pedigree above is:
6. The pedigree below traces the inheritance of a particular disorder. Circles are females, squares are males. Shaded symbols are affected with the disorder (NOTE: "half-shaded" symbols are NOT used here, for heterozygous individuals). What is the mode of inheritance of this disorder: is it dominant or recessive? Autosomal or X-linked? What is the genotype of the three numbered individuals? 1 2. 3.
6. A person is simultaneously heterozygous for two autosomal genetic traits. One is a recessive condition foralbinism (alleles A and a); this albinism gene is foundnear the centromere on the long arm of an acrocentricautosome. The other trait is the dominantly inheritedHuntington disease (alleles HD and HD+). TheHuntington gene is located near the telomere of oneof the arms of a metacentric autosome. Draw all copies of the two relevant chromosomes in this person asthey would appear during metaphase of (a) mitosis,(b) meiosis I, and (c) meiosis II. In each figure, labelthe location on every chromatid of the alleles forthese two genes, assuming that no recombinationtakes place.
9. Make a pedigree for each of the following situations. For each individual, write the individual's genotype (when possible) next to the individual's symbol (e.g. O xty, I Gg): a. Two parents do not have cystic fibrosis and they have a daughter with cystic fibrosis and a son who does not have cystic fibrosis. The daughter grows up and she mates with a male who does not have cystic fibrosis. Their only child is a boy and he has cystic fibrosis. b. A man with hemophilia mates with a female without hemophilia. They have one son and one daughter. The daughter has hemophilia and the son does not have hemophilia. The son grows up, and he marries and mates with a female. Their only child is a boy, and he has hemophilia.
5) Humans who have an abnormally high level of cholesterol are said to suffer from familialhypercholesterolemia.  The gene for this disorder is dominant (C). A man who isheterozygous for familial hypercholesterolemia marries a woman who is homozygousfor the recessive allele. What is the probability that they will have children that sufferfrom this disorder? please draw the puutnet square and also write the parents and gemtaics top the puutnet square thanks
36. Look at this pedigree and circle each row yes/no. Any assumption (that is not outrageous) can be made), for example, can assume someone is a carrier. a. Could this trait be inherited as a simple autosomal recessive? YES oo 8995 ON b. Could this trait be inherited as a simple autosomal dominant? YES ON C. Could this trait be inherited as a simple x linked recessive? YES ON d. Could this trait be inherited as a simple x linked dominant? YES ON e. Could this trait be inherited as a Y linked? YES ON
11. What evidence do you see in the pedigree illustrated if any, allowing the mode of inheritance for this trait to be deduced as completely vs. incompletely dominant? Do not consider any other information beyond what is shown in the pedigree. Answer in one complete sentence, referring to any individuals in the pedigree who may be informative using generation and individual numbers.
5. The pedigree to the right shows a pattern of inheritance for galactosemia, a rare autosomal recessive trait in humans where the enzymes that digest and utilize galactose are missing or defective. Shaded individuals have galactosemia. If individuals B and D want to get married, what is the probability that their first offspring will have galactosemia? A D в E а. 1/24 b. 1/16 с. 1/2 d. 1/12 е. 1/48 f. 1/4