2. You are designing a part for a piece of machinery. The part consists of a piece of sheet metal cut as shown below. The shape of the upper edge of the part is given by y, (x), and the shape of the lower edge of the part is given by y2(x). Y:(x) = h{ Y2(x) = h () dm Tem,dm b You are going to find the center of mass of the part. To find this, you must use calculus by breaking the part into small mass elements, dm's, that have a center of mass located at rem dm as indicated in the above diagram. You will then use an integral to sum up all of these small (differential) mass chunks. We will call the mass density per area for the sheet metal o which vou can assume is a constant.

Elements Of Electromagnetics
7th Edition
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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a, b, and c

2.
You are designing a part for a piece of machinery. The part consists of a
piece of sheet metal cut as shown below. The shape of the upper edge of the part
is given by y, (x), and the shape of the lower edge of the part is given by y2(x).
Y1(x) = h
y,(x)
y2(x) = h
b.
dm
Tem,dm
dx
b
You are going to find the center of mass of the part. To find this, you must use
calculus by breaking the part into small mass elements, dm's, that have a center
of mass located at em dm as indicated in the above diagram. You will then use an
integral to sum up all of these small (differential) mass chunks. We will call the
mass density per area for the sheet metal o which you can assume is a constant.
Transcribed Image Text:2. You are designing a part for a piece of machinery. The part consists of a piece of sheet metal cut as shown below. The shape of the upper edge of the part is given by y, (x), and the shape of the lower edge of the part is given by y2(x). Y1(x) = h y,(x) y2(x) = h b. dm Tem,dm dx b You are going to find the center of mass of the part. To find this, you must use calculus by breaking the part into small mass elements, dm's, that have a center of mass located at em dm as indicated in the above diagram. You will then use an integral to sum up all of these small (differential) mass chunks. We will call the mass density per area for the sheet metal o which you can assume is a constant.
If you are wondering how o relates to the mass density per volume (this is
normally what you refer to as the density of an object), p, it would be that o =
pw, where w is the thickness of the sheet metal.
a. For the dm shown, what is the area dA of dm in terms of y1, Y2, dx? We
are essentially asking you for the area of the little rectangle that we are
calling dm. This is a very simple question so don't try to overcomplicate it.
b. Because o is the mass per unit area, we can dm = odA. Use your answer
from the previous part to write dm in terms of o, y,(x),y2(x), dx.
c. Find the total mass of the part by adding up (integrating) all of the dm 's. To
do this, put everything in terms of x and compute the integral over x. Don't
forget about limits. You should find the answer to be
hb
m = o=
3
d. The vector iem,.âm is the position of the center of mass of our dm. Write
this vector in component from in terms of y, and y2.
e. We can now find the center of mass of our machine part by using the
definition of the center of mass
Tem
: Fem.dm dm
m
Substitute your expressions for Tem.dm and dm in terms of x and calculate
the integral to find the center of mass of the part. You should find the
answer to be
9
Tem
(bî + hŷ)
20
Transcribed Image Text:If you are wondering how o relates to the mass density per volume (this is normally what you refer to as the density of an object), p, it would be that o = pw, where w is the thickness of the sheet metal. a. For the dm shown, what is the area dA of dm in terms of y1, Y2, dx? We are essentially asking you for the area of the little rectangle that we are calling dm. This is a very simple question so don't try to overcomplicate it. b. Because o is the mass per unit area, we can dm = odA. Use your answer from the previous part to write dm in terms of o, y,(x),y2(x), dx. c. Find the total mass of the part by adding up (integrating) all of the dm 's. To do this, put everything in terms of x and compute the integral over x. Don't forget about limits. You should find the answer to be hb m = o= 3 d. The vector iem,.âm is the position of the center of mass of our dm. Write this vector in component from in terms of y, and y2. e. We can now find the center of mass of our machine part by using the definition of the center of mass Tem : Fem.dm dm m Substitute your expressions for Tem.dm and dm in terms of x and calculate the integral to find the center of mass of the part. You should find the answer to be 9 Tem (bî + hŷ) 20
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