2.Calculate the enthalpy change for the reaction :C4H4 (9) + H2 (9)C2H6 (g)Given the following data:i)C2H4 (9) + 3 O2 (9) → 2 CO2 (9) + 2 H2O (1)AH° = - 1410.9 kJ2 C2H6 (9) + 7 02 (9) →4 CO2 (9) + 6 H20 (1)ii)iii) 2 H2 (9) + O2 (g) 2 H2O (1)AH° = - 3119.4 kJAH° = - 571.6 kJ3.Calculate the standard enthalpy change for the reaction,C2H2 (g) + 2 H2 (9g) -C2H6 (9)Given that:i)2 C2H2 (9) + 5 02 (g) 4 CO2 (9) + 2 H2O (1)AH° = - 2599 kJ3119 kJii)2 C2H6 (9) + 7 02 (9) - 4 CO2 (9) + 6 H20 (1)AH° =iii) 2 H2 (9) + O2 (9) → 2 H2O ()AH° = - 572 kJThe enthalpy of combustion of methane is -891 kJmol-1. Calculate the enthalpy offormation of methane if the enthalpy of formation of carbon dioxide and water are -394 kJmol-1 and -286 kJmol respectively. Chemical equation for formation of4.methane:C(s) + 2H2(9)CH4(9)Given:AH = -891 kJmol-1CH4(9) + 202(9) 2H2O() + CO2(g)C(s) + Oz(g) → CO2(9)H2(g) + 2 O2 - H20AH = -394 kJmol-1AH = -286 kJmol-1

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2. Calculate the enthalpy change for the reaction : C4H4 (9) + H2 (9) - C2H6 (g) Given the following data: i) C2H4 (9) + 3 O2 (g) → 2 CO2 (9) + 2 H20 (1) AH° = - 1410.9 kJ AH° = - 3119.4 kJ ii) 2 C2H6 (9) + 7 02 (9) - 4 CO2 (9) + 6 H20 (1) iii) 2 H2 (9) + O2 (9) 2 H20 (1) AH° = - 571.6 kJ 3. Calculate the standard enthalpy change for the reaction, C2H2 + 2 H2 (9) C2H6 (9) (9) Given that: i) 2 C2H2 (9) + 5 O2 (9)4 CO2 (9) + 2 H2O (1) ii) 2 C2H6 (9) + 7 02 (9)4 CO2 (9) + 6 H20 (1) iii) 2 H2 (g) + O2 (g) → AH° = - 2599 kJ AH° = - 3119 kJ AH° = - 572 kJ 2 H20 (1) The enthalpy of combustion of methane is -891 kJmol-1. Calculate the enthalpy of formation of methane if the enthalpy of formation of carbon dioxide and water are - 394 kJmol1 and -286 kJmol respectively. Chemical equation for formation of 4. methane: C(s) + 2H2(9) → CH4(9) Given: CH4(9) + 202(9) C(s) + O2(9) → CO2(9) H2(9) + 2 O2 H20 AH = -891 kJmol1 AH = -394 kJmol1 AH = -286 kJmol1 2H201) + CO2(9)

2. Calculate the enthalpy change for the reaction : C4H4 (9) + H2 (9) - C2H6 (g) Given the following data: i) C2H4 (9) + 3 O2 (g) → 2 CO2 (9) + 2 H20 (1) AH° = - 1410.9 kJ AH° = - 3119.4 kJ ii) 2 C2H6 (9) + 7 02 (9) - 4 CO2 (9) + 6 H20 (1) iii) 2 H2 (9) + O2 (9) 2 H20 (1) AH° = - 571.6 kJ 3. Calculate the standard enthalpy change for the reaction, C2H2 + 2 H2 (9) C2H6 (9) (9) Given that: i) 2 C2H2 (9) + 5 O2 (9)4 CO2 (9) + 2 H2O (1) ii) 2 C2H6 (9) + 7 02 (9)4 CO2 (9) + 6 H20 (1) iii) 2 H2 (g) + O2 (g) → AH° = - 2599 kJ AH° = - 3119 kJ AH° = - 572 kJ 2 H20 (1) The enthalpy of combustion of methane is -891 kJmol-1. Calculate the enthalpy of formation of methane if the enthalpy of formation of carbon dioxide and water are - 394 kJmol1 and -286 kJmol respectively. Chemical equation for formation of 4. methane: C(s) + 2H2(9) → CH4(9) Given: CH4(9) + 202(9) C(s) + O2(9) → CO2(9) H2(9) + 2 O2 H20 AH = -891 kJmol1 AH = -394 kJmol1 AH = -286 kJmol1 2H201) + CO2(9)

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter5: Thermochemistry

Section: Chapter Questions

Problem 5.34QE

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