2+ In aqueous solution the Niion forms a complex with four cyanide anions. Write the formation constant expression for the equilibrium between the hydrated metal ion and the aqueous complex. Under that, write the balanced chemical equation for the first step in the formation of the complex. Kf = 3 + НО [Ni(H2O)¸ CN]** [H₂O] [Ni(H₂O)" [CN] 4 ロ→ロ Incorrect Your answer is incorrect. Write the First Step: First Step: 2+ (aq) → Ni + [Ni(H2O), (9) + CN (29) - [NI(H,O), CN ] (4) +_ ) 4 3 O|O ☐ ㅁ Example liganas displaces one of the water molecules coordinated to the metal. In this case, the first step towards the formation of the [Cu(NH3) 4 ] 2+ complex is this: [Cu(H₂O)4]²* (aq)+NH3(aq) → [Cu(NH3) (H₂O)¸]²* (aq) +H₂O (1) The last step is this: [Cu(NH3)3(H₂O)]²* (aq) +NH¸ (aq) → [Cu(NH3)4]²* (aq) +H₂O (1) It's the first of these equations that you need to enter in the second line. Note: be careful to keep track of the charge in these equations. Remember the total charge on the complex equals the difference between the charge on the metal cation and the charge on all the ligands. EO ANSWER Kf = [[Cu(NH3) 4 [[Cu(H₂O)4]²*][NH3]ª 2+ First Step: [Cu(H₂O)4]²* (aq) +NH3(aq) → [Cu(NH3) (H₂O)¸3]²* (aq) +H₂O (1)
2+ In aqueous solution the Niion forms a complex with four cyanide anions. Write the formation constant expression for the equilibrium between the hydrated metal ion and the aqueous complex. Under that, write the balanced chemical equation for the first step in the formation of the complex. Kf = 3 + НО [Ni(H2O)¸ CN]** [H₂O] [Ni(H₂O)" [CN] 4 ロ→ロ Incorrect Your answer is incorrect. Write the First Step: First Step: 2+ (aq) → Ni + [Ni(H2O), (9) + CN (29) - [NI(H,O), CN ] (4) +_ ) 4 3 O|O ☐ ㅁ Example liganas displaces one of the water molecules coordinated to the metal. In this case, the first step towards the formation of the [Cu(NH3) 4 ] 2+ complex is this: [Cu(H₂O)4]²* (aq)+NH3(aq) → [Cu(NH3) (H₂O)¸]²* (aq) +H₂O (1) The last step is this: [Cu(NH3)3(H₂O)]²* (aq) +NH¸ (aq) → [Cu(NH3)4]²* (aq) +H₂O (1) It's the first of these equations that you need to enter in the second line. Note: be careful to keep track of the charge in these equations. Remember the total charge on the complex equals the difference between the charge on the metal cation and the charge on all the ligands. EO ANSWER Kf = [[Cu(NH3) 4 [[Cu(H₂O)4]²*][NH3]ª 2+ First Step: [Cu(H₂O)4]²* (aq) +NH3(aq) → [Cu(NH3) (H₂O)¸3]²* (aq) +H₂O (1)
Chemistry by OpenStax (2015-05-04)
1st Edition
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Chapter15: Equilibria Of Other Reaction Classes
Section: Chapter Questions
Problem 65E: Sometimes equilibria fur complex ions are described in terms of dissociation constants. Kd . For the...
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