2) A bar of length 5 m is subjected to an axial tensile load of 100 KN. The bar is 25 mm diameter for 2 m of its length, 30 mm diameter for 1 m of its length, and 20 mm diameter for the remaining 2 m of its length. Taking E = 2 x 10° N/mm2. Calculate the total increase in length of the bar. %3D (Total increase in length = dl = 5.9 mm)
2) A bar of length 5 m is subjected to an axial tensile load of 100 KN. The bar is 25 mm diameter for 2 m of its length, 30 mm diameter for 1 m of its length, and 20 mm diameter for the remaining 2 m of its length. Taking E = 2 x 10° N/mm2. Calculate the total increase in length of the bar. %3D (Total increase in length = dl = 5.9 mm)
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter2: Axially Loaded Members
Section: Chapter Questions
Problem 2.2.7P: Rigid bar ACB is supported by an elastic circular strut DC having an outer diameter of 15 in. and...
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A bar of length 5 m is subjected to an axial tensile out of 100 KN The bar is 25 min diameter for 2 mof its length 30 mm diameter for I mor its length, and 20 mm diameter for the remaining 2 m of its length, Taking E= 2 x 10' Calculate the total increase in length of the bur.
![2) A bar of length 5 m is subjected to an axial tensile load of 100 KN. The bar is 25 mm diameter for 2
m of its length, 30 mm diameter for 1 m of its length, and 20 mm diameter for the remaining 2 m of
its length. Taking E = 2 x 10$ N/mm2. Calculate the total increase in length of the bar.
(Total increase in length = dl = 5.9 mm)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff3097d6e-c4af-4110-96a1-0ddcdbb5a644%2Ffa940868-75f1-44eb-9c15-fb3cca9a7b23%2F0gf03nd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2) A bar of length 5 m is subjected to an axial tensile load of 100 KN. The bar is 25 mm diameter for 2
m of its length, 30 mm diameter for 1 m of its length, and 20 mm diameter for the remaining 2 m of
its length. Taking E = 2 x 10$ N/mm2. Calculate the total increase in length of the bar.
(Total increase in length = dl = 5.9 mm)
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