18. The number of defects found in 25 samples of 100 Malossdientes Candy Company lemon drops taken on a daily basis from a production line over a five- week period is given in the worksheet Prob. 9-18. a. Compute dpmo and find the sigma level. b. Plot these data on a run chart. Can you identify any special causes?  C.  Explain what the Sigma Level means below:

Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter2: Introduction To Spreadsheet Modeling
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Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...
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18. The number of defects found in 25 samples of 100 Malossdientes Candy Company lemon drops taken on a daily basis from a production line over a five- week period is given in the worksheet Prob. 9-18.

a. Compute dpmo and find the sigma level.

b. Plot these data on a run chart. Can you identify any special causes? 

C.  Explain what the Sigma Level means below:

Malossdientes Candy Company
Run Chart
Number of VALUES (<= 30)
= Sample
Average
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
Sample
1
Defects
2
Center 5.88
2
4
Defects Center
7
6
4
7
3
3
4
3
9
8
9
15
11
2
7
7
8
3
7
25
1
4
5
8
2
4
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
5.88
Calculation of Sigma Value
1
1.5649
3
7
5.88
Enter number of samples
16
14
12
10
6
4
2
0
2
1.5
4
6
5.88
1
3.0649
2
5
4
5.88
3
4
6
7
5.88
5
1. Click the yellow cell, click on " button above. Select "statistical" from
category drop-down. Scroll down statistical selections. Find and select
2. NORM.S.INY dialog box will open. Type in the following into the "Probability"
text box: (1-.0588). Click OK. (see explanation to the right)
3. In the blue cell, type in the standard sigma shift (p469)
4. Sigma Level (value) will auto-calculate. Explain what the Sigma Level means
Copy Deleces colomm mito the genot vens detot. Jampre i matGNES TOY
7
3
5.88
6
7
8
3
5.88
8
9
4
5.88
9
10
10
3
5.88
Chart will auto-populate and format
11
11
9
5.88
12 13
14
12
8
5.88
15
13
9
5.88
16
14
15
5.88
17
18
A
Analyze chart data. Do not describe the chart!
Analyze and explain what the chart data means.
Incorporate analysis of the data, and your responses to the problem questions in
the text, in a narrative format using the Report Template.
15
11
5.88
19
The reason for the equation is we have to identify the probability of finding a value
between 1.000 and the mean of the distribution (0.0588 or 5.88)
20
16
2
5.88
21
22
17
7
5.88
23
24
18
7
5.88
25
19
8
5.88
--Defects
-Center
20
3
5.88
21
7
5.88
22
1
5.88
23
4
5.88
24
5
5.88
25
8
5.88
Transcribed Image Text:Malossdientes Candy Company Run Chart Number of VALUES (<= 30) = Sample Average 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 Sample 1 Defects 2 Center 5.88 2 4 Defects Center 7 6 4 7 3 3 4 3 9 8 9 15 11 2 7 7 8 3 7 25 1 4 5 8 2 4 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 5.88 Calculation of Sigma Value 1 1.5649 3 7 5.88 Enter number of samples 16 14 12 10 6 4 2 0 2 1.5 4 6 5.88 1 3.0649 2 5 4 5.88 3 4 6 7 5.88 5 1. Click the yellow cell, click on " button above. Select "statistical" from category drop-down. Scroll down statistical selections. Find and select 2. NORM.S.INY dialog box will open. Type in the following into the "Probability" text box: (1-.0588). Click OK. (see explanation to the right) 3. In the blue cell, type in the standard sigma shift (p469) 4. Sigma Level (value) will auto-calculate. Explain what the Sigma Level means Copy Deleces colomm mito the genot vens detot. Jampre i matGNES TOY 7 3 5.88 6 7 8 3 5.88 8 9 4 5.88 9 10 10 3 5.88 Chart will auto-populate and format 11 11 9 5.88 12 13 14 12 8 5.88 15 13 9 5.88 16 14 15 5.88 17 18 A Analyze chart data. Do not describe the chart! Analyze and explain what the chart data means. Incorporate analysis of the data, and your responses to the problem questions in the text, in a narrative format using the Report Template. 15 11 5.88 19 The reason for the equation is we have to identify the probability of finding a value between 1.000 and the mean of the distribution (0.0588 or 5.88) 20 16 2 5.88 21 22 17 7 5.88 23 24 18 7 5.88 25 19 8 5.88 --Defects -Center 20 3 5.88 21 7 5.88 22 1 5.88 23 4 5.88 24 5 5.88 25 8 5.88
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