12.37 Figure P 12.37 shows a group pile in clay. Determine theconsolidation settlement of the group. Use the 2:1 method toestimate the average effective stress in the clay layers.1335 KNK-3 m++3 m*18 m5 m3 m↓2.75 mX 2.75 mGroupplanFIGURE P12.37Groundwatertable15 mRockSandy = 15.72 kN/m²SandYsat = 18.55 kN/m³Normally consolidated clayYsat = 19.18 kN/m³€ = 0.8C = 0.8Normally consolidated clayYsat = 18.08 kN/m³% = 1.0C = 0.31Normally consolidated clayYsat = 19.5 kN/m³€ = 0.7C₂ = 0.26

12.37 Figure P 12.37 shows a group pile in clay. Determine the consolidation settlement of the group. Use the 2:1 method to estimate the average effective stress in the clay layers. 1335 KN 3m 3 m 18 m 5 m 3 m 2.75 m X 2.75 m Group plan Groundwater table 15 m Rock Sand y = 15.72 kN/m³ Sand Ysat = 18.55 kN/m³ Normally consolidated clay Ysat = 19.18 kN/m³ € = 0.8 C=0.8 Normally consolidated clay Ysat = 18.08 kN/m³ € = 1.0 C = 0.31 Normally consolidated clay Ysat = 19.5 kN/m³ € = 0.7 Cc = 0.26

12.37 Figure P 12.37 shows a group pile in clay. Determine the consolidation settlement of the group. Use the 2:1 method to estimate the average effective stress in the clay layers. 1335 KN 3m 3 m 18 m 5 m 3 m 2.75 m X 2.75 m Group plan Groundwater table 15 m Rock Sand y = 15.72 kN/m³ Sand Ysat = 18.55 kN/m³ Normally consolidated clay Ysat = 19.18 kN/m³ € = 0.8 C=0.8 Normally consolidated clay Ysat = 18.08 kN/m³ € = 1.0 C = 0.31 Normally consolidated clay Ysat = 19.5 kN/m³ € = 0.7 Cc = 0.26

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter18: Pile Foundation

Section: Chapter Questions

Problem 18.25P

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A group pile in clay is shown in the figure below. Determine the maximum vertical load Qg be applied if the allowable consolidation settlement of the pile group is set to be 0.17 m. Use the 2:1 stress distribution method to estimate the average effective stress in the clay layer. can Qg 3 m Sand Groundwater y = 15.72 kN/m3 table Sand 3 m Ysat = 18.55 kN/m3 2.75 m X 2.75 m Group plan Normally consolidated clay Ysat = 19.18 kN/m³ 15 m 18 m eo = 1 C. = 0,8 Normally consolidated clay Ysat = 19 kN/m3 eo = 0.25, C. =1 5 m Rock
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