12 2010 10 L90 15 Lo Za = 5 ohms Zb= 3-j4 ohms Zc= 2 ohms Zd = 12 ohms V1= 20 angle 0 V2 = 10 angle 90 V3 = 15 angle 0 1. Solve the branch currents of the circuit above using Kirchhoff's theorem. Solve neatly and correctly. Round off your solutions to 3 decimal places. Box your final answers. Answer: 5ampere 2. %24

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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12
2010
10 L90°
15 Lo
Za = 5 ohms
Zb= 3-j4 ohms
Zc= 2 ohms
Zd = 12 ohms
V1= 20 angle 0
V2 = 10 angle 90
V3 = 15 angle 0
1. Solve the branch currents of the circuit above using Kirchhoff's theorem.
Solve neatly and correctly. Round off your solutions to 3 decimal places. Box your final
answers.
Answer: 5ampere
2.
%24
Transcribed Image Text:12 2010 10 L90° 15 Lo Za = 5 ohms Zb= 3-j4 ohms Zc= 2 ohms Zd = 12 ohms V1= 20 angle 0 V2 = 10 angle 90 V3 = 15 angle 0 1. Solve the branch currents of the circuit above using Kirchhoff's theorem. Solve neatly and correctly. Round off your solutions to 3 decimal places. Box your final answers. Answer: 5ampere 2. %24
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