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- 75.0 mL of 0.500 M CuCl21. A 0.68 gram sample of a volatile liquid was heated to 358 K. The gas occupied 265 mL of space at a pressure of 0.95 atm. What is the molecular weight of this gas? PV = nRT and R = 0.082 atmL/moleK. (Make sure that all your units agree/match R)2. An aspirin sample, 0.62 grams, was titrated with 28 mL of 0.105 M NaOH solution. What is the percent purity of this aspirin sample? (MM of Aspirin = 180. g/mol)3. A sample of hydrate was heated thoroughly. How many waters of hydration are there if the anhydrous salt had a dry mass of 12 grams and a molar mass of 185 g/mol? The mass of water evaporated from the hydrate was 5.0 g.4.A sample of water (80 grams) had a temperature change of 6. ℃. What was the heat change of this sample? (q = m c ΔT, c = 4.18 J/ g ℃)5. A 6.0 gram sample of epsom salt, MgSO4 ·nH2O, was heated. After heating, 2.9 grams of anhydrous salt remained. How many waters of hydration does epsom salt contain?6. What is the theoretical yield of aspirin if you started your…Table 1. Standardization of HCI Solutions (40 pts) Trial Volume of HCI (To the nearest 0.01 mL) Molarity of NaOH (mol/L) Volume of NaOH (To the nearest 0.05 mL) Molarity of HCI* (mol/L) 1 20.00 mL 0.01011 10.40 0.0525 2 20.00 L 0.01011 10.50 0.0530 3 20.00 ml 0.01011 10.50 0.0535 4 20.00 mL 0.01011 10.60 0.0535 5 (If necessary) 20.00 mL 0.01011 10.50 0.0530 *Show calculations. Attach additional sheets of papers. According to experiment, the average molarity of our HCI solution is 0.0531 ± The uncertainty should cover the range of the experimental values. mol/L.
- Perform calculations to determine the amount of 5.00x10-5 M stock solution needed to prepare 20.00 mL of 2.00x10-5 M dye solution. Perform calculations to determine the amount of 2.00x10-5 M dye solution needed to prepare 20.00 mL of 5.00x10-6 M dye solution. Perform calculations to determine the amount of 5.00x10-6 M dye solution needed to prepare 20.00 mL of 1.00x10-6 M dye solution. Show your calculations170.0 mL of 0.12 M C2 H5NH2 with 285.0 mL of 0.20 M C2 H5 NH3 ClYou want to determine the concentration of NaCl in a water. In preliminary analysis, it appears to be saline water with a NaCl content of approximately 4%. Should you dilute the sample if your titrant has a concentration of 0.1 M and you want to spend 25 mL of sample?
- Part IV. Preparation of 100 mL 25% Solution X Materials: Solution X, measuring cylinder, distilled water, and parafilm. Show calculation steps. (1) Calculate the volume of Solution X required. (2) Calculate the volume of distilled water required_ (3) Deliver the calculated amount of distilled water in the measuring cylinder. (4) Add the calculated amount of Solution X to the measuring cylinder. (5) Seal the opening of the measuring cylinder with parafilm. Mix well. (6) Transfer the prepared 25% Solution X into a labelled container.7. Graduated cylinders can be used if an experiment calls for specific volumes but without the level of precision provided by volumetric glassware. A procedure calls for 15 mL of 10% NaOH to be added to 200 mL of DI water. Which graduated cylinder should be used to measure the NaOH solution? O 20 mL 50 mL 10 mL 100 mL63 gallons of a 26% acid solution are mixed with 44 gallons of a 80% acid solution. What is the acid concentration of the resulting mixture? Round to the nearest percent.
- I have to make a solution that contains Toluene, ethyl acetate, and glacial acetic acid With a ratio of 55:45:3. How do I convert this to mL? Toluene = 55 Ethyl acetate:45 Glacial acetic acid: 3What is the difference between analytical grade salt ( NaCl) and store-bought salt1. 500.0 mL 0.2 M KI2. 500.0 mL 0.2 M KCl3. 500.0 mL 0.1 M K2S2O84. 500.0 mL 0.1 M K2SO45. 500.0 mL 4.0 mM Na2S2O3 (from Na2S2O3∙5H2O)pls compelete the 2nd table given the data