10.0 ml sample of Mg2+ and Nat mixture was titrated against 0.02 M EDTA. It is required 20.0 ml of EDTA to reach end point. Then another 10.0 ml of the same sample was passed through cation exchange resin. The collected H* was titrated against 20.0 ml of 0.1 M NaOH using suitable indicator. calculate the concentration of Mg2+ in the sample in ppm. (Mwt Mg = 24.3 g/mol)

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter17: Complexation And Precipitation Reactions And Titrations
Section: Chapter Questions
Problem 17.42QAP
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10.0 ml sample of Mg2+ and Nat mixture was
titrated against 0.02 M EDTA. It is required 20.0
ml of EDTA to reach end point. Then another
10.0 ml of the same sample was passed
through cation exchange resin. The collected
H* was titrated against 20.0 ml of 0.1 M NaOH
using suitable indicator.
calculate the concentration of Mg2+ in the
sample in ppm. (Mwt Mg = 24.3 g/mol)
Transcribed Image Text:10.0 ml sample of Mg2+ and Nat mixture was titrated against 0.02 M EDTA. It is required 20.0 ml of EDTA to reach end point. Then another 10.0 ml of the same sample was passed through cation exchange resin. The collected H* was titrated against 20.0 ml of 0.1 M NaOH using suitable indicator. calculate the concentration of Mg2+ in the sample in ppm. (Mwt Mg = 24.3 g/mol)
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