1.4 4 (a) Calculate the value of Kc for the reaction: PC13 (8) + Cl₂ PC15 (8) Given that when 8.4 mol of PC15 (g) is mixed with 1.8 mol of PC13 (g) and allowed to come to equilibrium in a 10 dm³ container the amount of at equilibrium is 7.2 mol. PC15 (2) Kc = AH = Positive (b) Explain the effect of the following changes below on the value of Kc: (i) Increasing temperature (ii) Lowering the concentration of chlorine (C1₂) (iii) Addition of a catalyst

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Chapter13: Chemical Equilibrium
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1.4
4 (a) Calculate the value of Kc for the reaction:
PC13 (g) +
Cl₂ (8)
PC15 (8)
Given that when 8.4 mol of PC15 (g)
AH = Positive
Kc =
is mixed with 1.8 mol of PC13 (g) and
allowed to come to equilibrium in a 10 dm³ container the amount of
PC1, at equilibrium is 7.2 mol.
¹5 (g)
(b) Explain the effect of the following changes below on the value of
Kc:
(i) Increasing temperature
(ii) Lowering the concentration of chlorine (C1₂)
(iii) Addition of a catalyst
Transcribed Image Text:1.4 4 (a) Calculate the value of Kc for the reaction: PC13 (g) + Cl₂ (8) PC15 (8) Given that when 8.4 mol of PC15 (g) AH = Positive Kc = is mixed with 1.8 mol of PC13 (g) and allowed to come to equilibrium in a 10 dm³ container the amount of PC1, at equilibrium is 7.2 mol. ¹5 (g) (b) Explain the effect of the following changes below on the value of Kc: (i) Increasing temperature (ii) Lowering the concentration of chlorine (C1₂) (iii) Addition of a catalyst
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