1. In this experiment, you will make a set of solutions containing different concentrations of crystal violet (CV*) by mixing different volumes of a stock CV* solution with water to give final volumes of 3.0 mL. The stock solution of CV+ has a concentration of 2.0 x 10-5 M and is dark purple. The diluted solutions will be prepared in cuvettes. 2.0 x 105 M CV* (purple) H₂O V₁ diluted samples of CV* in cuvettes 3.0 mL= V2 Use c₁V₁= C₂V₂ to calculate the volume of the stock 2.0 x 105 M CV+ AND the volume of water to make a 3.0 mL sample of 7.5 x 10-6 M CV+. Show all of your calculations.
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- Extraction Pre-Lab Question 14 Status: Not yet answered | Points possible: 1.00 Type answer: Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calculate the volume (in mL) of the 1.410 M stock NaOH solution needed to prepare 250.0 mL of 0.1273 M dilute NaOH solution. here to search 2 F12 P Cla Hon00 mL of a diprotic acid primary standard solution was accurately prepared to a concentration of 0.1431 M. Three samples of this primary standard solution were used as samples in a titration to standardize an aqueous solution of sodium hydroxide, NaOH, which would be used as a titrant. Using the following table of data for the titration of the primary standard acid with NaOH, calculate the average concentration of NaOH. Trial # Volume of primary standard Initial titrant volume Final titrant volume 1 10.00 mL 8.21 mL 27.22 mL 2 10.00 mL 27.22 mL 46.23 mL 3 10.00 mL 30.28 mL 49.29 mL 0.1506 M 0.0753 M 0.0376 M 0.1431 M 0.0526 MSix 50.0 ml volumetric flask 1 through 6 are labeled. 10.00 ml of 2.00 x 10-1 M Fe(NO3)3 solution was then pipet into each volumetric flask. A 1.00,2.00,3.00,4.00 and 5.00ml of 2.00 x 10-3M NaSCN solution was then pipetted to flask 2 through 6 respectively. A sufficient amount of 0.10 M nitric acid was then added to each flask to make each a total volume of 50.00ml. Hint M1V1=M2V2 a)what would be the concentration of Fe(NO3)3 in 0.10M HNO3? b)what would be the concentration of NaSCN in 0.10M HNO3?
- Six 50.0 ml volumetric flask 1-6 are labeled. 10.00 ml of 2.00 x 101 M Fe(NO3)3 solution was then pipet into each volumetric flask. A 1.00,2.00,3.00,4.00 and 5.00ml of 2.00 x 10-3M NaSCN solution was then pipetted to flask 2 through 6 respectively. A sufficient 0.10 M nitric acid was then added to each flask to make them total volume of 50.00ml. 1.a)Calculate the final Fe(NO3)3 concentrations for each. 1.b)Also how would you find the initial concentration of SCN- for each flask? Please show calculations to solutions.ThanksThe standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with DI water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. What is the corrected absorbance of both solution A and B? OA. Solution A: 0.123 Solution B: 0.463 O B. Solution A: 0.463 Solution B: 0.234 O C. Solution A: 0.123 Solution B: 0.234 O D. Solution A: 0.234 Solution B: 0.463The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with DI water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. What is the corrected absorbance of both solution A and B? A. Solution A: 0.123 Solution B: 0.463 B. Solution A: 0.463 Solution B: 0.234 C. Solution A: 0.123 Solution B: 0.234 D. Solution A: 0.234 Solution B: 0.463
- The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with DI water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. What is the corrected absorbance of both solution A and B? O A. Solution A: 0.123 Solution B: 0.463 O B. Solution A: 0.463 Solution B: 0.234 O C. Solution A: 0.123 O D. Solution A: 0.234 Solution B: 0.234 Solution B: 0.463Procedure: Step 1: Pipet 25 mL of prepared sample solution, which has been prepared into a 250 mL Erlenmeyer flask. Step 2: Add 3-5 drops of phenolphthalein indicator solution to the sample solution in the 250 mL Erlenmeyer flask. Step 3: Rinse the buret with three 10 mL portions of standardized 0.1 M HC1 acid solution, before fill this acid solution into the buret and record the initial volume of this acid solution in the burette. Step 4: Titrate the sample solution with the standardized 0.1 M HC1 to the endpoint and record the final volume of this acid in the burette. (Note: phenolphthalein endpoint is from pink color to colorless) Step 5: Repeat the titration for two more times. Step 6: Repeat the same procedure from step 1 to step 5 by using methyl orange as an indicator rather than phenolphathelein. (Note: methyl orange endpoint is from orange to red color). Calculate the alkalinity of the sample for both the indicators and potentiometric method using the following equation: [Alk]…A 20.330 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 74.044 g of water. A 10.245 g aliquot of this solution is then titrated with 0.1074 M HCl. It required 29.47 mL of the HCl solution to reach the methyl red endpoint. Calculate the weight percent NH, in the aqueous waste. wt% NH3 = APR 9 $ 4 R dº 10 % . 5 Search or type URL n T tv < 60 ♫ MacBook Pro A Y & N 7 907 U * 8 00 + I A ( 9 © | O - O W P J { + [ % ] delete
- The standard addition method is used to analyze a sample of a river water for mercury. Solution A is made by pipetting 5.00 mL of undiluted sample in to a 10 mL volumetric flask and filling to the mark with D water. Solution B is made by pipetting 5.00 mL of undiluted sample and 3.00 mL of 15.0 ppb of Hg standard into same 10.0 mL volumetric flask and filling to the mark with DI. Solution A and B are analyzed using atomic absorption spectroscopy and give a percent transmittance values of 56 % and 33 % respectively (not blank corrected). A blank has a transmittance of 96%. Which of the following technique can be used to determine the amount of mercury in the undiluted sample of river water? O A. IR spectroscopy O B. Cold vapor atomic absorption OC. Hydride generation atomic absorption OD. Electrothermal atomic absorptionA K2SO4 solution is prepared by weighing out a certain amount of the pure solid reagent,dissolving it to 500.0 mL in a volumetric flask. An aliquot was taken from this solution.of 25.00 ml and diluted to 500.0 ml. An aliquot of 5.00 was taken from this new solution anddiluted to 50.00 ml. A chemical analysis of this new solution showed a 0.100%(w/v)in K+. Calculate the weight of the pure solid K2SO4 used for the preparation of the original solution.and its concentration in each volumetric flask. The answer is 2.23x10^2gMeasure the mass of 0.400g of Co(NO3)2 + 6H2O and dissolve it in 15mL of distilled or deionized water using a clean beaker Then while using a graduated cylinder, measure out 10.0mL of a prepared 0.10-M Na3PO4 soultion. Determine which compound Na3PO4 or Co(NO3)2 *6H2O will be the limliting reagent. Then detrimine the theiretical yeild