ONLY question 2 b)so what I would like you to do is read the questions and read the feedback and fix my answers thats all here is the question : Here is the feedback : You still did not take into consideration that the combined masses are moving when the spring is compressed. Find speed of combined mass at maximum compression using Momentum equation PTI = PTF and then use Energy Equations to solve for the spring constant. Ek1 + Ek2 = EkT + EE Where EE is the elastic energy stored in the spring. Then use EE = 0.5kx2 to solve for khere is my answer : fix it correctly and give me the final answer : Mass of cart 1 (m₁) = 1.2 kgInitial velocity of cart 1 (v₁₁) = 6.0 m/sMass of cart 2 (m₂) = 1.8 kgInitial velocity of cart 2 (V₂i) = 0 m/sMaximum compression of the spring (x) = 2 cm = 0.02 mThe maximum compression of the spring occurs when all the kinetic energy is converted intopotential energy in the spring. The potential energy stored in a spring is given byP.E. =-=kx²where k is the spring constant and x is the displacement (compression in this case).The potential energy stored in the compressed spring is equal to the initial kinetic energy of thesystem,The potential energy of the spring = Initial kinetic energy1/1/2xKxx²== 1/2 xm₁ × (v₁,;)² + 1/{ xm₂×(√₂₁)²X11/12×-×k×(0.02 m)² = —×(1.2 kg)× (6.0 m / s)² + 1 ×(1.8 kg)× (0 m/2(0.0002 m²) xk = 21.6 J+ 0 J21.6 J0.0002 m²k= 108000 N/m(b) The spring constant is 108000 N/m.K= 1. A ball with a mass of 10.0 g hits a 5.0 kg block of wood tied to astring, as shown. You may assume that there is no friction from thestring. The ball hits the block in a completely inelastic collision, causingthe block to rise to a maximum height of 8.0 cm. Find the initialhorizontal speed of the ball. You may assume that the string is verylong.|||Ah = 8.0 cmPress here for long description2.A 1.2 kg cart moving at 6.0 m/s [E] collides with a stationary 1.8 kgcart. The head-on collision is completely elastic and is cushioned by aspring.a. Find the velocity of each cart after the collision.b. The maximum compression of the spring during the collision is 2.0cm. Find the spring constant.

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Answered: 1. A ball with a mass of 10.0 g hits a…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter8: Momentum And Collisions

Section: Chapter Questions

Problem 15P

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ONLY question 2 b)

so what I would like you to do is read the questions and read the feedback and fix my answers thats all

here is the question :

Here is the feedback :

You still did not take into consideration that the combined masses are moving when the spring is compressed. Find speed of combined mass at maximum compression using Momentum equation P_TI = P_TF and then use Energy Equations to solve for the spring constant. E_k1 + E_k2 = E_kT + E_E Where E_E is the elastic energy stored in the spring. Then use E_E = 0.5kx² to solve for k

here is my answer : fix it correctly and give me the final answer :

Mass of cart 1 (m₁) = 1.2 kg
Initial velocity of cart 1 (v₁₁) = 6.0 m/s
Mass of cart 2 (m₂) = 1.8 kg
Initial velocity of cart 2 (V₂i) = 0 m/s
Maximum compression of the spring (x) = 2 cm = 0.02 m
The maximum compression of the spring occurs when all the kinetic energy is converted into
potential energy in the spring. The potential energy stored in a spring is given by
P.E. =-=kx²
where k is the spring constant and x is the displacement (compression in this case).
The potential energy stored in the compressed spring is equal to the initial kinetic energy of the
system,
The potential energy of the spring = Initial kinetic energy
1/1/2xKxx²=
= 1/2 xm₁ × (v₁,;)² + 1/{ xm₂×(√₂₁)²
X
11/12×
-×k×(0.02 m)² = —×(1.2 kg)× (6.0 m / s)² + 1 ×(1.8 kg)× (0 m/
2
(0.0002 m²) xk = 21.6 J+ 0 J
21.6 J
0.0002 m²
k= 108000 N/m
(b) The spring constant is 108000 N/m.
K=

1. A ball with a mass of 10.0 g hits a 5.0 kg block of wood tied to a
string, as shown. You may assume that there is no friction from the
string. The ball hits the block in a completely inelastic collision, causing
the block to rise to a maximum height of 8.0 cm. Find the initial
horizontal speed of the ball. You may assume that the string is very
long.
|||
Ah = 8.0 cm
Press here for long description
2.A 1.2 kg cart moving at 6.0 m/s [E] collides with a stationary 1.8 kg
cart. The head-on collision is completely elastic and is cushioned by a
spring.
a. Find the velocity of each cart after the collision.
b. The maximum compression of the spring during the collision is 2.0
cm. Find the spring constant.

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