1. A 1.2-gram sample of lanolin was treated with Wij’s solution and excess potassium iodide solution. The liberated iodine reacted with 30 ml of 0.1 N sodium thiosulfate solution. If the iodine value was determined as 12.69, what is the volume used in blank titration?

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Chapter1: Chemical Foundations
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Problem 113CP: On October 21, 1982, the Bureau of the Mint changed the composition of pennies (see Exercise 120)....
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Atomic weights are not provided, but please use rounded-off values to the nearest whole number.
(examples: 24.305, use "24"; 107.8682, use "108"; 1.00784, use "1"; 15.999, use "16")

Add trailing zeros to complete your answer to the 3rd decimal place, if necessary.
(examples: if your answer is "62.7", write it as 62.700;
if your answer is "37.12", write it as 37.120
if your answer is "123", write it as 123.000)

1. A 1.2-gram sample of lanolin was treated with Wij’s solution and excess potassium iodide solution. The liberated iodine reacted with 30 ml of 0.1 N sodium thiosulfate solution. If the iodine value was determined as 12.69, what is the volume used in blank titration?

2. A 500mg oil sample is taken from a conical flask and is dissolved in 50mL distilled alcohol. An indicator is added and is then titrated against 0.112N KOH until a slight pink color appears. It took 17.6mL of the titrant to reach the endpoint. What is the sample’s Acid Value?

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