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- Explain ur answers plsexe/lo_u-lgNsikr7j8P3jH-IQs_dp5pR4ENzvdYC-70kXyMz36BqJhw3sVPj_jpaFLxvGArYxlbmcyqa71YYPJBG6RjdYAdGPjGhFLILID-HEX1YcqAB?1oBw7QYjlbavbSPXtx-YCjsh_7mMmrq#item Course Home Login | Student Veri... Bb Logout MyrogrammingLab Imported From IE ITEC2110:Summer2.. TunesToTube - Upl.. Web Development. Publix App O KINETICS AND EQUILIBRIUM Using the Arrhenius equation to caiculate k at one temperature fr.. Ci The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy E = 54.0 kJ/mol. If the rate constant of this 1 -1 at 11.0 °C, what will the rate constant be at -16.0 °C? reaction is 0.012 M Round your answer to 2 significant digits. -1 -1 x10b Compounds) the starting material and reagent росіз Show the missing Conc HBr Br + -Br o
- Blackboard | Miami D x M CHM 1046L_Week 9 x S HOL - Instance A ALEKS - Daniela GALL x Blackboard| A www-awu.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslikr7j8P3jH-liGmxpvVN4ENzvdYC-70kXyMz36BqJhw3sVP20GT MEASUREMENT AND MATTER Simplifying unit expressions Rewrite this measurement with a simpler unit, if possible. kg-m 4.7 2 m m Note: If you can simplify the unit at all, it may be possible to make more than one simplification. Be sure ロ.口 ola5- help plsу. [1] (CH3)2CULI [2] H20 Br NaCN SOCI2 [1] LIAIH4 [2] H,O CH3OH, H* [1] DIBAL-H PCC [1] CH3LI H. [2] H2O [2] H2O [1] LIAIH4 [2] H2O (CH3CO)20 NaCN K L [1] CH3M9B. M TSCI, pyridine [2] H20
- Cengage Learnir × | Cengage Learnir x | Cengage Learnir X OWLv2 | Online X × Ar Ex3 CH 14 and 15 prod03-cnow-owl.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?lo Question 1 1pt This question has multiple parts. Work all the parts to get the most points. Question 2 1pt Question 3 Question 4 2 pts 2 pts Data in the table were collected at 540 K for the following reaction: Question 5 1 pt CO(g) + NO2(g) → CO2 (g) + NO(g) Initial concentration (mol/L) Initial rate Question 6 Question 7 2 pts 1pt [CO] [NO2] (mol/L. h) 5.1 × 10-4 Question 8 Question 9 2 pts 1pt Question 102 pts Question 111pt 0.35 x 10 4 3.9 × 10-8 5.1 x 10-4 0.70 × 10-4 7.9 x 10-8 5.1 × 10-4 0.18 × 10-4 2.0 × 10-8 1.0 × 10-³ 0.35 × 10-4 7.7 × 10-8 Question 12 1 pt 1.5 x 10-3 0.35 × 10-4 1.2 × 10-7 Question 13 1 pt Question 14 1pt Question 151 pt a Determine the reaction order with respect to each reactant. Order with respect to CO: 1 ✓ ✓ 4 Order with respect to NO2: 1 V✓ Progress: 13/15 items Due Mar 28 at…Qd 170.II URULURUL. C7Y H A www-awn.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-lijkPWvZoZLqkt1FLIq7wcPWKzBYGfE9IMFjvvh3x_rzônaF9YTN80Bms6y067EgyeOUwHKJOrzx.. O STOICHIOMETRY Using molarity to find solute moles and solution volume A chemist adds 340.0 mL of a 0.118M potassium dichromate (K,Cr,0,) solution to a reaction flask. Calculate the millimoles of potassium dichromate the chemist has added to the flask. Round your answer to 3 significant digits. |mmol Explanation Check O 2021 McGraw-Hill Education. All Riahts Reserved. Terms of Use I Privacy Ace の @ étv MacBook Air
- pleas ehelp 6LEKS X A ALEKS-Allie Fleming - Learn X + wu.aleks.com/alekscgi/x/Isl.exe/10_u-IgNslkr7j8P3jH-IQUHIQg6bJxmeSyVpHOEB1plef9xyC5Ca9QIFwtxr00buHbeXUZhX-WNTXJ1_nmqsj0g EocTE5oCPLW220suaHKGGrEdkEV2?10... # 3 E O ADVANCED GENERAL CHEMISTRY Using the general properties of equilibrium constants At a certain temperature, the equilibrium constant K for the following reaction is 0.0056: N₂(g) + O₂(g) 2 NO(g) Use this information to complete the following table. Suppose a 18. L reaction vessel is filled with 0.40 mol of NO. What can you say about the composition of the mixture in the vessel at equilibrium? $ V What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. 2 NO(g) N₂(0)+ O₂(9) What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. 3 N₂(0)+30₂(0) 6 NO(g) Explanation -- A 59 R F 1/ 48 % Check 5 ■ T G d- ^ Q Search 6 4+ Y H & 7 all fo O There will be very little N₂ and 0₂. O There will be very…Use this video to answer the questions: https://www.youtube.com/watch?v=BocfSXdbaU0