Pt1420 Unit 3 Problem 1-3 Answer

After Tuesday's shipment was unloaded, a manager found that 7, or 28 percent, of the items in the shipment were either dented or scratched. How many items were received on Tuesday?

After that, I'd have to see if the one’s place had a one because, the multiples of 7 that ended with one would qualify for getting a remainder of 1 if I divided by 2,3,4,5, and 6.But, things that work out for me is finding multiples of 7 that didn’t end in 1 because, I’d thought most of them didn’t have to end in one but,

34. The type of code that uses only seven bits for each character is ____.

7. It’s the sequence appears to be random but in fact does repeat typically after some lengthily period of time. FHSS requires

[1, 4, 7, 10, 13, 16, 19, 22, 25, 28, 3, 6, 9, 12, 15, 18, 21, 24, 2,

3. If the digits repeat in a series of steps: for example advancing positions from a point to another like in this series: 01-44-45 23-01-34 33-41-01.

Now I take the larger number and minus the smaller number 1719 – 728 = 991

10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 55 OR

Converting 0111 to decimal number: (23 x 0) + (22 x 1) + (21 x 1) + (20 x 1) = 7

1.8) 7 * j = 1 (mod 20) we then use calculator and j equals 3

By dividing both values by 7 we get 21/7 : 133/7 = 3 : 19

6, 7, 33, 71, 73, 74, 76, 94-98, 103, 105, 128, 131, 133, 135, 139

14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7,

As given iin the example given, 26,847. We added 2,6,8,4and 7 to get the sum, 27 which is a perfect number. Perfect numbers are numbers that are equal to the sum of their proper factors. And we divided 27 by 9 so we get 3. Since the quotient is a whole number it is a multiple of 9. We know that 27 is a multiple of 9 because when we count..

am 6.5. Rounded to the nearest whole number, I am 6. If the sum of my digits is