p250 Fa23 Exam 1 vA (1)
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Physics/BioPhysics 250
Fall 2023 - Exam #1
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This is a one hour and 50 minute, closed book exam.
You may use a calculator; please do not share calculators.
The exam includes 20 multiple choice questions which will be machine graded. Each question is worth 5 points. No partial credit will be given.
You may use one 8.5×11” sheet of paper with hand-written notes written on both sides.
If you are stuck on a problem, move on and come back to it.
Constants
you
might
need
𝑘𝑘 = 8.99 × 10
9
N m
2
/C
2
𝜀𝜀
0
= 8.85 × 10
−
12
C
2
/N m
2
𝑔 = 9.8 m/s
2
Speed of sound in air at 20C = 340m/s
Density of air at 20 C = 1.20 kg/m
3
Magnitude of the electron charge: 𝑒 = 1.6 × 10
−19
C Mass of the proton: 𝑚
𝑝 = 1.67 × 10
−27
kg
Mass of the electron: 𝑚
𝑒 = 9.11 × 10
−31
kg 1 electron volt (1eV) = 1.6 × 10
−19
J Avogadro’s Number: 𝑁
𝐴 = 6.02 × 10
23
/mol Threshold of hearing 𝐼
𝑜
= 10
−12
W/m
2
milli(m) = 10
−3
, micro(
𝜇
) = 10
−6
, nano (n) = 10
−9
pico (p) = 10
−12
, femto(f) = 10
−15
kilo (k) = 10
3
, mega (M) = 10
6
, giga (G) = 10
9
Passage for questions 1-3: The Stethoscope
A stethoscope is a medical device for listening to sounds inside the human body. It commonly consists of
a chest piece that is connected to PVC tubing, which then splits into two shorter metal tubes that direct the sound to the ears of the physician. The chest piece often has two sides: an open “bell” to better hear
low-frequency sounds, and a similarly shaped hollow cavity that is covered with a flexible membrane, the diaphragm, for higher-pitched sounds. Use 𝑣 = 340 𝑚⁄𝑠 for the speed of sound and 𝜌 =
1.2
𝑘𝑔⁄𝑚
3
for the density of air for the problems below.
1.
If the bell has a diameter of 25 mm on the open side that is pointing towards the patient, and the two eartips have circular openings with a diameter of 2.5 mm, by how much has the total sound intensity that reaches the physician’s ears increased, compared to what entered the bell?
Assume that there are no losses in the tubing.
A.
It did not increase.
B.
By a factor of 5
C.
By a factor of 10
D.
By a factor of 50
E.
By a factor of 1000
2.
It is sometimes asserted that the bell is particularly good at amplifying low-frequency sounds below 100Hz because those sounds can excite standing waves in the air inside the bell, with one
end open (towards the patient) and the other end almost closed. Do you believe this, based on what you know about the physics of standing waves and the basic geometry of the stethoscope?
A.
Yes, this is plausible.
B.
No, the bell is too small to accommodate standing waves at these frequencies.
C.
No, the bell is too large to accommodate standing waves at these frequencies.
D.
No, because standing waves need closed ends on both sides in order to form.
E.
No, because the open end becomes a closed and when pressed against the patient’s chest,
and no sound will enter the bell.
3.
A physician can hear sounds at a frequency of 100 Hz if the sound at the diaphragm has an intensity of at least 10
-10
W/m
2
. What is the displacement amplitude at the diaphragm for this
sound?
A.
15 pm
B.
1.1 nm
C.
11 µm
D.
0.3 mm
E.
12 mm
END OF PASSAGE QUESTIONS
4.
Four traveling waves are described by the following equations, where all quantities are
measured in SI units and y represents the displacement.
I. 𝑦 = 0.12 cos(−1.5𝑥 + 2𝑡)
II. 𝑦 = −0.12 cos(2𝑥 + 1.5𝑡)
III. 𝑦 = −0.02 cos(3𝑥 − 4𝑡)
IV. 𝑦 = 0.02 cos(−2𝑥 + 2.5𝑡)
Which of these waves have the same speed?
A.
I and II
B.
I and III
C.
I and IV
D.
II and III
E.
III and IV
5.
A phon is an experimentally derived unit of human-perceived loudness. A person perceives sound at 800 Hz to be 40 phons, which corresponds to an intensity level of 40dB (from the graph). The person hears a different sound at 100 Hz to also be 40 phons, which corresponds to 60 dB. Approximately what is the ratio of the intensity of the 800 Hz sound to the 100 Hz sound,
i.e. what is 𝐼
800𝐻𝑧
/𝐼
100𝐻𝑧
?
A. 100
B. 0.050
C. 0.01
D. 20
E. 0.10
Intensity level (dB)
6.
Two speakers are set up and connected to the same 1000 Hz signal source. When you stand at a
particular location between the two speakers you find that the two speakers individually produce a wave with amplitude 𝐴
. When both speakers are powered, you expect:
A.
An amplitude which goes from 0 to 𝐴
, as the phase difference of the sound coming from
the two speakers changes from 0 to 2𝜋 radians.
B.
An amplitude of 𝐴 when the phase difference of the sound coming from the two
speakers at your position is 0.
C.
An amplitude of 4𝐴 when the phase difference of the sound coming from the two
speakers at your position is 0 radians.
D.
An amplitude which goes from 0 to 2𝐴 as the phase difference of the sound coming
from the two speakers changes from 𝜋 to 2𝜋 radians.
E.
The phase difference of the sound coming from the two speakers at your position is
always zero.
7.
A guitar string plays a “G” note with a frequency of 196Hz when it is tuned to a tension of 70.0
N. A guitarist wishes to “bend” the note to a G# with a frequency of 207.65Hz. This is done by
changing the tension in the string without appreciably changing its length. What string tension
is required to play a G#?
A. 72.1 N
B. 68.0 N
C. 66.1 N
D. 74.2 N
E. 78.6 N
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QUESTION 19
Power of the Human Heart. The human heart is a powerful and extremely reliable pump. Each day it takes in and discharges
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a. Convert this number to meters (1 kilometer = 10° meters) and express it using scientific notation:
150000000000
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How else might you express this number? (Millions, billions, etc. ?)
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Use the equation distance = velocity x time, or time = distance / velocity.
Time = distance/velocity = ,
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How many days?.
_days
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b.What is the approximate age of the universe indicated by that erroneous value of Ho? Express your answer in years to one significant figure.
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A molecular cloud has a temperature of 46 K and an HI cloud has a temperature of 135 K. What are their wavelengths of maximum intensity?
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In what region of the electromagnetic spectrum can the radiation from these clouds be found?
Part 1 of 3
We can use Wien's Law to determine the wavelength of maximum intensity in nanometers for the molecular cloud.
2.90 x 106
Amc
Amc
Amc
XHI
^HI
=
AHI
=
We can use Wien's Law again to determine the wavelength of maximum intensity in nanometers for the HI cloud.
2.90 x 106
II
=
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nm
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explain why each piece of evidence you cite supports the Dark Energy model.
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29.A shopper in a supermarket pushes a cart with a force of 35 N directed at an angle of 25° below the horizontal. The force is just sufficient to
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Below are birds-eye views of six identical toy cars moving to the right at 2 m/s. Various forces act on the cars with magnitudes and directions indicated below. All forces act in the horizontal plane and are either parallel or at 45 or 90 degrees to the
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Rank these cars on the basis of their speed a short time (ie. before any car's speed can reach zero) after the forces are applied
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5 N
5 N
5N
-2 m/s
'5N
10 N
10 N
T)
2 m/s
5 N
2 m/s
2 m/s
5N
5N
5 N
10 N
2 m/s
2 m/s
O
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Pozitif x ekseni boyunca, 8,0 m/s sürati ile hareket eden 3,0 kg kütleli bir cisim, kütlesi M
olan ve başlangıçta duran bir başka cisimle, tek boyutlu esnek bir çarpışma
gerçekleştiriyor. Çarpışmadan sonra, kütlesi M olan cismin hızı, eksenin pozitif yönünde
ve 6,0 m/s'dir. M kütlesi nedir?
A 3.0 kg object moving at 8.0 m/s in the positive direction of an x axis has a one-
dimensional elastic collision with an object of mass M, initially at rest. After the collision
the object of mass M has a velocity of 6.0 m/s in the positive direction of the axis. What is
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О 20 kg
O 3,0 kg
1,0 kg
O 4,0 kg
O 5,0 kg
Sürtünmesiz, 0;=30° açılı bir eğik düzlem üzerinde bulunan m=3,0 kg kütleli bir kutu,
kütlesiz bir sicim ile, açısı O2=60° olan başka bir eğik düzlem üzerinde bulunan m-2,0 kg
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4. Express 7,726,000 in scientific notation:
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5. Express 0.0008751 in scientifie notation with :
a) with 1 Significant Figure(SFs). b) with 2 SFs .c) with 3 SFs. d) with 4 SFs
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I Review | Constants
Light of wavelength 490 nm illuminates a double
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g =
X Your answer is incorrect.
The Sun has a mass of 2 x 1030 kg and the distance from the Sun to Mars is 2.3 x 10¹¹ m. If Mars had no mass, there would still be
a small gravitational force on an object near Mars's surface, due only to the Sun. What would be the value of g on (massless) Mars,
due to the gravitational force of the Sun? Assume that Mars's radius is negligible compared to the distance between the Sun and
Mars.
i
Hint
-
F2
eTextbook and Media
Window Help
F3
This problem is equivalent to assuming that there is a spherical surface surrounding the Sun, and finding the value of g on that
surface. The radius of the surface is the same as the distance from Sun to the other body.
OCT
20
80
N/kg
F4
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5…
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I keep getting undefined with my equation how do I set this up?
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Question 7/13
Two students are working together to build a birdhouse. Student 1 applies a force of 10 N to a wooden board in order to slide it across the table to Student 2. If the
force of friction resisting the student's push is 4 N, what is the net force acting on the board?
What is allowing the board to overcome the force of friction and slide across the table?
(A A constant balanced force from student 1 is causing the board to slide across the table.
B An unbalanced force from student 1 is causing the board to move across the table
Reverse friction allows the board to be affected by the balanced force from the table and
slide
D Force of friction is allowing the board to move across the table.
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