Assignment 3 Final
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ASSIGNMENT – 3
FACILITY PLANNING & DESIGN
Need to produce 250 units of a final assembly, C. Assembly C is comprised of 2 sub-assemblies, A
and B.
Final assembly C has defect rate of 1%.
Six (6) pieces of sub-assembly A are needed for the final product C.
Sub-assembly A has a defect rate of 14%.
One (1) pieces of sub-assembly B are needed for the final product C.
Sub-assembly B has a defect rate of 10%.
I.
Draw a simple work flow diagram or “road map” for this process. Label the sub-assemblies and
yields at each step.
Answer.
Following is the work flow diagram for the given process:
Note:
Work Flow Diagram is drawn on https://www.lucidchart.com ;URL Link for the pdf document is as follows - https://lucid.app/publicSegments/view/2a897e97-e3a2-41aa-9316-78b43161902a II.
Calculate the number of sub-assemblies A and B needed to produce 250 units of final product C. DO
NOT round-off to more than 2 places.
Answer.
Given: Number of Sub-assemblies A required for final assembly = 6 pieces
Number of Sub-assemblies A required for final assembly = 1 piece
Number of Final assemblies required to be produced = 250 units
Sr.
No.
Description
No. of units to be produced
in ideal condition
(Process yield = 100%)
Defect Rate
(in %)
Yield
(in %)
No. of units to be produced
in given condition
1
Final Assembly C
250
1%
99%
250
99%
=
252.53
2
Sub-assembly A
250*6=1500
14%
86%
252.53
∗
6
86%
=
1761.84
3
Sub-assembly B
250*1=250
10%
90%
252.53
∗
1
90%
=
280.59
Total number of Final assemblies C to be produced = 252.53 ≈
253 units
Total number of Sub-assemblies A to be produced = 1761.84 ≈
1762 units
Total number of Sub-assemblies B to be produced = 280.59 ≈
281 units
Note:
For calculation of number of units to be produced, numbers are rounded off up to 2 decimal places. As the assemblies can not be produced in fractions, next whole number is taken in order to finally get 250 units of final assemblies C.
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