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Conestoga College *

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TCOMM8040

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Electrical Engineering

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Apr 3, 2024

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Path loss For the following free-space formula: 1. Modify it to accommodate system losses like line and connector losses, fading margin and diversity gain. You will probably find it advantageous to put everything into decibel form. Ans1 : - Pr (dB)=Pt (Db)+Gt(dB)+Gr(dB)+20log 10 ( Lambda 4 Pi r ) –(Ls+Fm+Gd) Here 2. Now, suppose that the path loss coefficient is n = 4. Modify your equation to accommodate this. Ans2 : - The modified Pr equation for the path loss coefficient is Pr (dB)=Pt (Db)+Gt(dB)+Gr(dB)+10nlog 10 ( Lambda 4 Pi r ) –(Ls+Fm+Gd) 3. Suppose that you have a system operating at 1940 MHz ( uplink). The system conforms to the cellular model with path loss coefficient = 4. Calculate the cell radius given the following system data: minimum receivable power for the base station is -110 dBm Pt = 45 dBm (GSM) Transmit antenna is 60⁰ beamwidth antenna with gain = 17.1 dB Receive antenna has a gain of 2.1 dBi. cable is 30m long with losses of 0.2 dB/m. connector losses: 0.2 dB. jumper losses: 0.5 dB.
Path loss Ans3 : - Pt =45dbm Pr=-110 dbm Cable losses=0.2 db/m (for 30m cable =total cable losses =6db) =0.15453 m =154.639 x 10 3 Km Using Free space formula, 40log 10 ( Lambda 4 Pi R ) = -167.5 R= 189.5 m 4. Now, perform the cell radius calculation for path loss coefficient = 2. Comment on the difference. Ans: - Now, path loss coefficient=2 -110=64.2+20*log 10 ( Lambda 4 Pi R )-6.7 20log 10 ( Lambda 4 Pi R ) = -110-64.2+6.7 log 10 ( Lambda 4 Pi R )= 167.5 20 5. To determine path loss, do we need to know the initial and final powers? Ans5: - The initial power is the power with which the signal is transmitted, and the final power is the power that is received after the signal has traveled through the medium. The difference between these two values gives us the path loss, which is a measure of how much signal strength is lost during transmission. This loss can be due to various factors,
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