Skills Challenge 2- Determination of Unknown Concentrations Post lab submission
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Skills Challenge 2
Determination of Unknown Dye Concentration – Post Lab Submission
Names and Contributions: (list all team members and their contributions using the CRediT system outlined in the Teamwork Module: Listing Contributions on Assignments. Make sure to indicate the corresponding author as the one who submits the assignment.)
Taylor Hamilton: Author, Conceptualization, Analysis, Data Curation, Writing - Original Draft, Writing - Review & Editing Tyler Deal: Methodology, Investigation, Visualization, Writing –
original draft, Writing –
Review and editing Ryan Magner: Data Curation, Investigation, Analysis, Methodology, Writing –
original draft, Writing –
Review and editing Description of the unknown:
clear blue liquid List each measuring device used and state its uncertainty:
(For example, 50-mL volumetric flask –
uncertainty
0.05 mL) •
5-mL graduated cylinder
0.05mL
•
25-mL volumetric flasks ±0.05 cm Method:
(
Be concise and comprehensive, use grammatically correct complete sentences in past tense, passive voice, paragraph format)
The unknown dye was found via a systematic approach that included numerous steps. Initially, the known dye stock with 0.500 ppm was diluted several times for the first dilution 4ml of the stock dye was added to a 5 mL graduated cylinder then the rest of the cylinder was filled up with water to the 5 mL marker. This combined solution was now 80% concentration. Next, 3mL of the stock dye was poured into a 5 mL graduated cylinder, and the remainder of the cylinder was filled with water to the 5 mL marker, resulting in a 60% concentration. 2mL of the stock dye was poured into a 5 mL graduated cylinder, and the remainder of the cylinder was filled with water to the 5 mL marker, yielding a 40% concentration. 1mL of the stock dye was poured into a 5 mL graduated cylinder, and the remainder of the cylinder was filled with water to the 5 mL marker, yielding a 20% concentration. These concentrations were then put into cuvettes. Two other cuvettes were filled, one with water, and one with just the stock dye. One more cuvette was filled with a 50/50 solution of the unknown dye and water using the previous method. Then all the cuvettes are run through a spectrometer to determine the absorption value of each. Each abs value had to be below 1 or the results would be
inaccurate. A graph was created using the determined abs values and dilutions to calculate the rest of the results. Results: (Include data table(s) for property measured in identifying the concentration in the unknown sample. Show data for solutions used to obtain the standard curve and the unknown.) Table 1 : Percent Dilutions of Stock Dye and Unknown Dye plus their Absorption Values Percent Dilutions of Stock Dye Absorption Values 100% 0.9067 80% 0.7098 60% 0.5210 40% 0.4462 20% 0.1704 Percent Dilution of Unknown Dye Concentration Absorption Value 50% 0.8199 What is the independent variable? % dilutions of solutions What is the dependent variable? Absorption value Include the standard curve (including equation and R
2
) generated from Excel (or other graphing software): Absorption Values of Different Dilutions Figure 1: This graph depicts the mostly linear increase in absorption values as percent dilutions increase to 100%. As well as the equation for the trend line and a R^2 value close to 1.
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Experiment 605_Hydrates_1_2_1 (1) (Protected View) - Word (Unlicensed Product)
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Post-lab Questions
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1. Calculate the mass percent of water for the hydrate, LINO,-3H;O.
2. What will be the probable effect if you kept the crucible completely covered during the entire
heating and cooling processes? Would your calculated percent water in the hydrate be high, low, or
unaffected? Explain.
3. If 2.752 g sample of Ca(NO:); XH;O is heated to constant mass, the residue weighs 1.941 g.
Determine the value of x and the formula of the hydrate.
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Data Collection
Kinetic Data Collection
Time, t (s)
Volume of added base (mL)
First addition
40
0.50
Second addition
101
1.00
Third addition
160
1.52
Fourth addition
224
1.99
Fifth addition
278
2.49
Sixth addition
334
3.01
Seventh additlon
389
3.48
Calculations
Concentration of NaOH stock solution:
0.01 M
Concentration of t-BuCl stock solution:
0.2 M
Volume of t-BuCl solution:
10 mL stock stock solution added to 25 mL acetone
Table view
List view
Kinetic Data
Volume of
Moles of Amount of
t-Bucl
(mol)
[-Buc]
In[-BuC
Time, t (s) added base added base
(mL)
(mol)
First
addition
40
0.50
Second
additlon
101
1.00
Third
addition
160
1.52
Fourth
addition
224
1.99
Flfth
additlon
278
2.49
Sixth
additlon
334
3.01
Seventh
addition
389
3.48
Use the data in the table above to plot In[t-BuC]]; vs time (s). Include labelled axis, a title, and a
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Of which reactant are there the least initial moles? Enter its chemical formula:
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1. Construct a standard curve in Excel by plotting concentration (in ppm) on your x-ax
(unitless) on your y-axis for your known solutions. Label the axes on the graph and provi
title. See Figure 5 in the lab handout for an example. Use a linear trendline to generate a
data. Label the graph with the equation and the R2 value. Insert your labeled graph in the
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Nitrate Standard Curve
3
4
ty=0.8842x-0.8191
R²=0.9509
Q..**.
Concentration
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6
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2. Using the equation from your graph, determine the nitrate concentration (in ppm) in each of
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