08_03_lab_report

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Somerset High School *

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4455

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Chemistry

Date

May 10, 2024

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docx

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2

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Solutions Lab Report Instructions: Complete all sections of this report and answer all questions in complete sentences for full credit. Solutions Pre-Lab Questions Complete the pre-lab questions to get the values you need for your drink solutions. 1. Calculate the molar mass of powered fruit drink mix, made from sucrose (C 12 H 22 O 11 ). c = 12.01(12) = 144.012- h = 1.008(22) = 22.176- o = 16.000 (11) = 175.989- 342.177 g/mol 2. Determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL. M = mol/liters- mol = M(L)- mol = (1.0M)(.100L)- 0.1 mol- 34.218 g Use molarity = moles of solute (mol) ÷ liters of solution (L) to calculate the amount of drink mix, in moles. Then convert moles to grams using a mole conversion: moles = grams/molar mass 3. What mass of powdered drink mix is needed to make a 0.5 M solution of 100 mL? 34.218/2 = 17.109G Data Taste Texture Color Control 1.0 M without heat Sweet and strong Grainy Dark red 0.5 M without heat Strong and very sweet Smooth Dark red 1.0 M with heat Bittersweet Sporadically grainy Light red 0.5 M with heat Bittersweet, more sweet Smooth Light red 1.0 M with stir Strong and sour Very grainy Dark red 0.5 M with stir Strong and sour, but kinda sweet Smooth Dark red 1.0 M without stir Sour Very grainy Light red 0.5 M without stir Bittersweet Smooth Light red 1.0 M with sugar Sweet Smooth Very dark red 0.5 M with sugar Dull Smooth Very dark red 1.0 M w sugar cubes Sweet Smooth Very dark red Unless Otherwise Noted All Content © 2022 Florida Virtual School. FlexPoint Education Cloud™ is a trademark of Florida Virtual School.
0.5 M w sugar cubes Dull Smooth Very dark red Conclusion Using complete sentences, write a conclusion that addresses the following: The purpose of the lab, what you explored, what you learned What the effects of temperature, agitation, and particle size had on solubility. A statement identifying the solubility factors that changed the mixture the most. A statement identifying the solubility factor that changed the mixture the least. Post-Lab Connection Questions Answer questions in complete sentences and show work. 1. If you were working for a beverage company, which molarity would you recommend, and what directions for mixing would you create for the drink package? Support your claims using the data you collected. A 0.5m solution of the drink combined with hot water and a good stir will, in my opinion, lead to a better particle dissolving and improve the drink's flavor. 2. If you needed to make 100 mL of a 0.2 M fruit drink solution from the 1.0 M fruit drink solution, how would you do it? (Hint: Use M s V s = M d V d to find the amount of concentrated solution you need, then add water to reach 100 mL.) Show your work. M1v1 = m2v2- (Co.2m)(0.100l) = (1.0m)x- x = 0.02l- = 20.0ml of 1m solution; add 80 ml water Unless Otherwise Noted All Content © 2022 Florida Virtual School. FlexPoint Education Cloud™ is a trademark of Florida Virtual School. My conclusion was that the mixture tends to become more smooth and sweet when the temperature and stirring speed are raised. Additionally, I deduced that the 1.0 m solution is far more potent than the 0.5 m solution.
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